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Very simply, the field of the positive and negative elements of the dipole "almost" cancel out - but not quite. It is because they are some small distance away that there is a residual (third order) term. You can see this by taking two charges $+q$ and $-q$ at a distance $2d$, and look at the field a distance $r$ from the center of the two (on the same ...


1

In diamagnetic material a magnetic dipole moment will develop in presence of external field. Magnetic dipole moment per volume is: $$\mathbf{M}=\chi\mathbf{H}= {\chi\mathbf{B} \over \mu}={1 \over \mu_0}{\chi \over \chi+1}\mathbf{B}$$ In a non-uniform magnetic field there would be a force on a magnetic dipole: $$\mathbf{F}=\nabla ...


0

Nuclei have a very small electric dipole moment. However, they can have a significant quadrupole moment, which influences hyperfine structure. You can refer to the Wikipedia article to get a quick understanding of the latter.


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Neither the nucleus nor the electrons form electric dipoles of any kind - the electron is a point charge, a monopole; the nucleus contains only one type of charge, the positive protons (and the electrically neutral neutrons). There is no scope for electric dipole interactions between the nucleus and electrons. The nucleus can still have an electric ...


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The general equation for electric field due to dipole at a point is KP/R^3[(1+3cos^2(thetha)]^1/2. When (thetha=90 it is equitorial line and when (theta=0) it is axial line from the above equation we get the required results ie KP/R^3 and 2KP/R^3



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