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The minimum uncertainty says that ΔyΔP_y = hbar/2, where Δy is half of the width of the slit, and ΔP_y will give you the linear momentum in the y direction. If you divide ΔP_y by the mass m of the electron, cca. 1-^{-27}gr., you get Δv_y, the velocity in the y direction, ( equal to minus velocity in the -y direction). To get the width of the pattern on the ...

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I think I understand it a little better now so I decided to post my thought and obviously won't accept my own answer. My understanding is that A(k) is the space of wave vectors, however we know these only differ by direction not magnitude for the diffracted wavepacket (Rayleigh scattering). Therefore the function A(k) indicates the "spread" of the ...

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Molecules of air are all around us all the time. If so, during daylight do rays from the sun diffract as it passes through molecules in the air? and if so is this diffraction negligible to be noticed? plus does this affect anything? While both diffraction and scattering refer to redirection, I think scattering is the better term here. The molecules in ...

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Re: diffraction of light by molecules in the air. The distances between atoms in molecules is approximately $0.1 nm$ which is about $5000$ times smaller than the wavelength of visible light. For diffraction effects to occur the structure should have similar dimensions to the wavelength of light - in this case the molecules are just too small for ...

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This looks like an interference pattern like the type created by a diffraction grating. Note that to the left and right there are little rainbows with the red outermost and then green and blue innermost. Also the further away from the centre the wider the rainbows get. These features are characteristic of diffraction grating type phenomena. Now here the ...

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Well done on your careful and correct thoughts, particularly about the diffraction from an infinitessimally thin annulus. If, the lens were perfect and we had a thin annulus (and by thin, we mean much less than the wavelength) then the output field would indeed be significantly different from the superposition of waves with wavevectors lying on a cone; ...

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The diffraction grating acts as an array of light sources. Each slit in the grating emits light, and you calculate the fringe positions by calculating the path lengths from all these sources/slits and identifying the points where the phase differences are multiples of $2\pi$. However, as you usually do the calculation you assume the incident light is normal ...

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