New answers tagged dielectric
3
Not always. All of your Gaussian surface should be in a linear dielectric with constant electric permittivity $\epsilon$ to be able to use gauss law and derive that formula. With this conditions it's true most of the times.
Here you can use again the gauss law:
$\vec D = {Q_a \over 4 \pi r^2} \hat r$
But we know that for linear dielectrics: $\vec D = ...
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