# Tag Info

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As stated in the answer you linked, the density of a black hole is defined by the ratio of its mass over the volume spanned by its Schwarzschild radius. That does not mean that there is actually uniformly distributed matter inside the Schwarzschild radius. All of the matter is packed very densely (in something with the characteristic length of the Planck ...

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consider ten kg substance .Take few kg substance and measuring mass density,the density is same as before substance. so we can say that from above explanation,density is an intensive property.

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So, per JQK's suggestion, I began from the equation $\text(a)$ $$\frac{\frac{n^2}{\mu}-1}{\frac{n^2}{\mu}+2}=\frac{1}{3\epsilon_0}\frac{N}{V}\alpha$$ where $N$ is the number of gas particles, and $\alpha$ is molecular polarizability. From the ideal gas law $$PV=zRT$$ it follows that $\frac{N}{V}=\frac{N_A\rho}{M}$. Thus ...

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You have to account for the local fields and how they change as the density changes. Look up the Clausius–Mossotti Equation and its derivation.

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The density of air can be calculated from the ideal gas law $$\rho_\textrm{air}(p,T)=\frac{p}{R_\textrm{ specific }T}$$ where $p$ is pressure in Pascal and $T$ temperature in Kelvin. At $300^\circ ~\textrm{C}$ and $100~\textrm{kPa}\,,$ dry air has a density of $\rho_\mathrm{300k,1atm}=1.177~\mathrm{kg\cdot m^{-3}}$ (source) The average molar mass of air is ...

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density = mass / volume so all you need to do is get your volume constant find the volume of air @ 300 k then it is all the same

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Take one of the "floats" at the lower end of the temperature range, and find a way to accurately determine its mass (easy) and volume (harder), and calculate its density, noting the temperature tag that is attached. Take another float at the upper end of the temperature range and do the same. Just for grins, to ensure that your data are linear, choose a ...

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If I understand your description ("the tube is on an angle") correctly, then the "outer" wall of the tube is where the centrifugal force is pointing - and the "inner" wall is the opposite side. When the tube is spinning, there will be an apparent radial force on all the particles - the lighter particles will experience a "buoyancy" towards the inner wall, ...

2

Very interesting question. As you wrote yourself in your Edit it is hard to describe water via the ideal gas model. You have to introduce at least two important improvements of your ideal gas: Dipole - Dipole - Interaction instead of no interaction. Let's call this pair potential $V_d$ and note that for two given molecules $V_d$ is not only distance but ...

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Warmer water doesn't sink at any temperatur unless it is an iceberg and the coldest water floats. Vibrating atoms tend to move to slower moving atoms evening out. Vortexes could from the temperature change in the pot or in the ocean only then may you see warmer water lower than cold water in a continuous flow.

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You will need a box ( or a bathtub ) with a plain control of the volume of water and some inflatable balloons whose volume can be changed, controlled and measured 1 ) ( exactly ) immerse the body part to be measured in a liquid at rest. 2 ) Attach the balloons to the feets, 3 ) adjust the volume of the inflatable balloons to cancel the buoyancy , as you ...

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With some prior measurements such as total mass, volume of lower and upper body. I think you can use these techniques to figure the mass of just lower body. Computerized Tomography (CT) and Magnetic Resonance Imaging (MRI) These two imaging techniques are now considered to be the most accurate methods for measuring tissue, organ, and whole-body fat mass as ...

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[PDF] A Modified Approach to Homogeneity Testing at … www.icdd.com/resources/axa/vol42/V42_09.pdf Here is one method that may suffice. A new method is presented in this paper which is based both on the information mass concept and on modified statistical test procedures. With this approach the homogeneity assessment for all microanalytical techniques, ...

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You can check fractional distillation which is used to separate mixture with components having different boiling points which is true in your case.

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Cool the mixture to condense the water or absorb the water in (say) dry Calcium Chloride.

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