# Tag Info

You understand that $\mathcal C$ violation is required, as if it weren't, processes related by $\mathcal C$ that violated baryon number conservation would balance, i.e. $$P \to Q B \qquad \mathcal C:\qquad \overline P \to \overline Q \, \overline B$$ would result in no net baryon number violation. In these expressions, $B$ is a fermion carrying baryon ...