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Acceleration due to the Coriolis effect: $a_C=−2\Omega\times v$ Then $\Omega=2\pi/day$ $v=45m/s$ and thus $aC=−0.0065m/s2$ Horizontal displacement $d$ is given by $$d=1/2a_Ct^2$$ Using earlier estimate of $5.2s$ flight time for a ~200m drive: $$d=−18cm$$



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