# Tag Info

Suppose you're standing at the edge of an enormous merry-go-round. You'll feel a "force" that seems to be pushing you outwards. This is the centrifugal force. The centrifugal force is the force you feel because you're at a certain distance away from the axis of rotation. It is written as $\vec{F}_{\rm centrifugal} = m~\vec{\omega} \times (\vec{r} \times ... 2 Look in Wikipedia http://en.wikipedia.org/wiki/Coriolis_effect. For understanding intuitively the Coriolis force effect, assume an object moving according to a static (inertial) frame of reference, in the plane perpendicular to the rotation axis, and along the radius, In the rotating frame, see the animation in Wikipedia, the Coriolis force imposes an ... 3 The Coriolis force$\vec F_{\text{coriolis}} = -2m \, \vec \omega \times \vec v$only depends on velocity. The centrifugal force$\vec F_{\text{centrifugal}} = -m \, \vec \omega \times (\vec \omega \times \vec r)$only depends on position. Finally, if the object is not rotating uniformly ($\dot {\vec \omega} \ne 0\$), then yet another fictitious force comes ...