# Tag Info

## New answers tagged coriolis-effect

1

The Coriolis acceleration is $2\vec{v}\times\vec{\omega}$, where the velocity vector $\vec{v}$ is measured in the rotating reference frame. In your example, if I'm reading you right, the particle is moving with the disc, so $\vec{v}=0$, so the Coriolis acceleration is zero. In general, if you have either a radial or tangential velocity component in the ...

1

According to these lecture notes, the Coriolis parameter at mid-latitudes is on the order of $f_c = 1\times10^-4 \text{s}^{-1}$ and this needs to be multiplied by a wind speed to get a force. This is the first important note -- Coriolis forces do not create wind/motion, they merely change the direction of it. For a pressure force, let's look at a ...

0

The Coriolis force is dependent of the uxΩ (u and Ω being vectors). This is the cross product between the velocity of the mass and Ω which is the angular momentum of the rotating frame with respect to the moving mass. So, for a mass on one of the hemispheres, the angular velocity vector is pointing upwards(normal to the Earth's surface) while for a mass ...

Top 50 recent answers are included