New answers tagged charge
1
The charge is produced by rubbing between the socks (or feet) and the bed of the trampoline, and by cloths rubbing on skin as he jumps. This is called the triboelectric effect. Grounding the frame of the trampoline will not make much difference because the bed is not normally a conductor unless wet.
The solution is to change the clothes he is wearing, ...
0
It might be the specific combination of sock material and trampoline material that's to blame: some combinations will transfer a charge, some won't. Socks of a different material might mitigate this; there are a number of "anti-static socks" on the market, but I'm not sure any of them come in three-year-old sizes.
Has he tried trampolining barefoot?
1
Get a grounding rod and bang it into the ground? Get 2 ground clips and 1 meter of 6mm grounding wire. Link 1 clip to the leg of the trampoline and then the other clip to the grounding rod.
0
Field lines originate from +ve and end at -ve charge. So its clear A and C are -ve and B is +ve. OK?.... now no. of lines originating from B over total solid angle 4pi is 10
no. of lines ending at A and C over total solid angle 4pi is 5
so |B|/|A|=10/5=2, and |B|/|C|=10/5=2
so B is 2 times A and C and +ve>>>2q
A nd C are -q
so option (d) is ...
0
Induction is the process of appearance of opposite charge on the surface of a neutral conductor,when a charged body is brought near it.
5
It's not intuition.It's a problem which can be solved.
First we identify the sign of the charges. By seeing the direction of field lines we can see that the sign of charges. Field lines originate from $+ve$ and end at $-ve$ charges.
Next by Definition of Flux,
The number of field lines cutting per unit surface surface .
And Gauss' Law
The flux ...
0
Re your edit 1, if the system consisted solely of plates B and C you would be correct: the opposing charges would create an electric field (and potential difference) between them that would cause charge to flow.
However, there is more to the system than plates B and C. In particular, the charge on plate A creates an electric field that exactly cancels that ...
1
then why is there no potential difference between the two capacitors
It's not quite clear what you mean here but do understand that charged capacitors are electrically neutral.
When a capacitor is "charged", it is not electrically charged, it is energy charged in the same sense as when we say a battery is charged.
There is nothing mysterious about two ...
0
Bear in mind that capacitance is a function of Area and distance between plates,
Connecting all the capacitance in series effectively increase the distance between the plates
thus decreasing the total capacitance under the same voltage
When connecting them in parallel, across the same voltage but the effective area is increased, therefore the capacitance ...
3
The electric field intensity is usually defined in introductory textbooks as the limit
$$\lim_{q\rightarrow0}\frac{\mathbf F}{q},$$ i.e. the force on a test charge, per unit charge, when that test charge goes to zero. However, you are right in noting that the limit $q\rightarrow 0 $ is impossible to take because charge is quantized, and you can never have ...
1
The electric field of earth is really quite complicated. This paper is old, but presents a nice overview of the issues. That $500\,000\, \mathrm{C}$ number is related a charge separation between the surface and the bottom of the ionosphere, rather than the net charge on the earth. And in any case, it is only the result of a rough model whose underpinnings ...
0
You say:
since electricity's displacement is very slow ?
I suspect you mean the electron drift velocity in metallic conductors is low, but that's completely different to the electron transport in a lightning bolt.
I'm not sure the mechanism of conduction in a lightning bolt is fully understood, but consider this. The dielectric breakdown of air ...
0
A more "straight" answer to your question, is:
Q = V x C, = V x (K A/d). Q = charge; V = voltage, C = capacitance; K = permittivity constant; A = surface area holding the charge; d = distance between the surfaces holding the charge.
The formula changes, depending on the shape of the surfaces - parallel plates, cylinders, spheres, etc. and any dielectric ...
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