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There is no analogy of "voltage", "current", "charge" or "flux" to electromagnetism for the weak force, at least none that would be helpful. The reason for this is that all of these are classical concepts, while the notion of the weak force is completely quantum. Taking the classical limit just makes it vanish because the classical force law of forces with ...


I understand also that there would be a tiny minuscule resistive loss through the wire, but really it's not enough to say anything about. On the contrary, it's crucial. Assuming an ideal voltage source (can supply unlimited current) of voltage $V_S$, an ideal resistor of resistance $R$, and an ideal uncharged capacitor of capacitance $C$, are ...


You refer to plates, so I assume we are talking about a parallel plate capacitor. In this case (to a good approximation) the field is the same everywhere inside the capacitor so if the field is bigger than $E_b$ somewhere inside the capacitor then it is bigger than $E_b$ everywhere. But if the capacitor is not a parallel plate capacitor all bets are off. ...


When you connect a battery to a capacitor, a "real" circuit has at least four components in series: the voltage source (battery) the capacitor series resistance series inductance Any wire has inductance, since current flowing through it will induce a magnetic field. It is possible to have wires without resistance - we call them superconductors. So let's ...


The question is more about battery chemistry than physics, but here are some things to keep in mind: Capacitors can typically retain MUCH less charge than a battery, since the latter stores energy in chemical form Supercapacitors are a class of capacitor that can be used for precisely the purpose you describe. From the Wiki page: Supercapacitors are ...


No. The capacitors are in series. This is because one side is at the same potential. But it looks like parallel. If you apply Kirchoff's Loop Law, you will see that they are in series. And in that way too, you will get that answer. Hope that helps.


NO. The Capacitors are in series as when we go from one capacitor to another we find no junction in between.

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