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Total charge required by your batteries is $Q_b = 4 \times 100 A.h = 400 A.h$ Maximum current supplied by generator is $I_g = 3 \times 5 A = 15 A$ So the time taken to charge the batteries is $400/15 = 26.67 hrs$ Now to calculate the energy required to heat 500L ($m$=500kg) of water from 30°C to 50°C (ie: increase temp by $\Delta T=20K$), we can use: \$H ...