Tagged Questions
4
votes
1answer
83 views
Strange Grassmann double integration
I can unterstand why because the integration over Grassman variables has to be translational invariant too, one has
$$
\int d\theta = 0
$$
and
$$
\int d\theta \theta = 1
$$
but I dont see where ...
1
vote
3answers
135 views
Constructing Supersymmetric Lagrangians
It is a very trivial doubt but somehow I am not able to figure it out. While constructing a supersymmetric lagrangian we always even number of fermionic fields.
One reason is of course the product ...
1
vote
1answer
129 views
dimensional analysis of Grassmann integration/differentiation
There is another paradox that I need to resolve:
The Berezin integration rules for Grassmann odd variables give the same result as differentiation:
If $f=x+\theta\psi$ is a superfunction, the ...
1
vote
1answer
117 views
Superspace Uncertainty Principle
Do the "operator for translations in superspace" and the "position in superspace operator" follow an uncertainty principle? How "real" is superspace? Aside from being weird (and possibly just a ...
3
votes
1answer
242 views
Basic Grassmann/Berezin Integral Question
Is there a reason why $\int\! d\theta~\theta = 1$ for a Grassmann integral? Books give arguments for $\int\! d\theta = 0$ which I can follow, but not for the former one.
