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Difference between $|0\rangle$ and $0$ in the context of isospin
I know this has been asked before, but I am confused having read it in the context of isospin, where the creation operators act on the "vacuum" state (representing no particles) $$a^\dagger_m|0\rangle ...
Nov 7 '11 at 7:16
newest isospin-symmetry vacuum questions feed
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