Tagged Questions
1
vote
2answers
331 views
Duality and Fourier Transforms [closed]
I read that
$(FF(f))(x)=2\pi f(-x)$, where $F$ is the Fourier transform
and $F(f(x-a))(k)=\exp(-ika) X(k)$ where $X(k)=F(f(x))$
implies $F(\exp(iax)f(x))(k)=X(k-a)$.
But I don't see how that is ...
