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A 6500-kg helicopter accelerates upward at 0.60 m/s² while lifting a 1200-kg car. (a) What is the lift force exerted by the air on the rotors?
(b) What is the tension in the cable (ignore its mass) that connects the car to the helicopter?

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closed as too localized by Mark Eichenlaub, David Z May 18 '11 at 9:37

This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center.If this question can be reworded to fit the rules in the help center, please edit the question.

    
    
consider this a warning that you should stop posting low-quality questions (such as homework problems). The link that Mark posted should help explain why these kinds of questions are not appropriate. –  David Z May 18 '11 at 9:40
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1 Answer 1

Force = (Mass)*(Acceleration)

Use the above equation to:

1.) find the force required to accelerate the helicopter and car 0.60 m/s² (NOT upward)

2.) find the force required to counteract the acceleration due to gravity (9.8m/s²) for both the car and the heicopter

3.) adding 1. and 2. together will equal the lift force exerted by the air on the rotors

4.) do the same thing as in 1-3 except for only the car, which will yield the tension in the cable.

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