Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

I'm looking for resources on the computation of (I think) very simple Feynman diagrams for QCD processes. The processes are q'qbar' -> qqbar and gg->qqbar (only at tree level, no loops involved) and my main problem is the computation of the colour factors.

I'm not interested in the absolute value of the cross-section, but in the angular distribution (in terms of cos theta). At least for the gg->qqbar process I think I need the correct factors though, to correctly add the diagrams.

I've already looked into the Quantum Field Theory book by Peskin, but there I only found the final cross-sections but not the calculation.

share|cite|improve this question
up vote 2 down vote accepted

ALthough I haven't read the book myself, I would recommend Quantum Chromodynamics by Walter Greiner, Stefan Schramm and Eckart Stein. I have gone through another book of the same authors, and they show lots of details in their calculation (i.e. they avoid sentence like: "one can show that blablabla leads to the following equation"). Furthermore, their books have plenty of exercises with detailed answers, so I would assume that they have explicit calculations of Feynman diagrams.

P.S. your name suggests that you might be German-speaking, and so you can read the book in its original language.

share|cite|improve this answer
Thank you, I will definitely try this book! – DerKuchen Feb 20 '14 at 17:38
@DerKuchen No problem. If you don't like it, then please let me know as I am thinking of buying the book myself at some point in the (long-term) future. – Hunter Feb 20 '14 at 17:47

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.