# Why does a faraday cage protect you from high currents?

In an electrostatic case it is clear that that in a space enclosed with a conductor (without charge in it) the electric field is zero.

This is often demonstrated in physics shows like on the following image:

However it you have the lighting a current is flowing through the air and through the cage. So wie are not in the electro- static situation anymore since we have currents, i.e. moving charges.

How can one account in the explanation properly that we have moving charges?

Some people say that the fact that the man inside the cage is safe doesn't have to do anything with faradays cage, it's simply because the the cage is a better conductor. Sometimes also the skin-effect is mentioned.

So what's true. It would be great do get a detailed and correct explanation of this. Do you have any good references?

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Faraday's cage is known to block static and non-static electric fields. The mechanism of blocking depends on whether the electric field is static or non-static (EM field). I suppose you question is about how the cage works in non-electrostatic case.

In EM case (time changing field), two scenarios could happen. The first is electric discharge where the current flows from a distant electrode to the cage. The second is an EM wave with high power propagating toward the cage generating its current locally within the conductor. I will explain how the cage works for both cases.

With respect to the first case, it can be mathematically described by charge continuity equation (equation 3 in this link). This equation basically relates the current flowing through a conductor to the charge accumulating in it.

What happens in the first scenario is that the external current (being moving charges) coming from the electrode accumulates at the point where it (the spark or the streamer) hit the cage. Because the cage is a conductor the charge continuity equation tells us that the local accumulation of charge where the spark hit the cage will cause current to flow within the conductor to remove that accumulation. The characteristic time required to remove the accumulation is called the relaxation time. It can be derived from charge continuity equation. For the derivation have a look at pages 57-59 of this document. I think that is taken from a book called Elements of Electromagnetics chapter 5.

If the conductor is made from a material with infinite conductivity, the relaxation time is zero. That means the current will keep flowing though the cage without any problem and that the electric field in the conductor is ALWAYS zero. In other words, the electrostatic point of view holds even for non-electrostatic case if the conductivity is infinite. That is a direct consequence from charge continuity equation. For non infinite conductivity cases, the electric field within the conductor will survive within the conductor with a time scale related directly to relaxation time of that conductor. I hope it is clear now with respect to first case.

The second case is related to EM waves where they generate their currents locally within the conductor, that is where the skin effect comes into play. An EM wave penetrates into a conductor the Skin effect occurs. In general, EM waves when they penetrate a conductor they are attenuated until their fields become almost zero. A characteristic depth of penetration is called Skin depth. The skin depth is the distance it takes an EM wave to be attenuated to certain value. This skin depth depends on many factors such as conductivity and frequency, the following figure taken from Wikipedia shows the skin depth of different materials for different frequencies:

For the cage to protect from EM waves, it is thickness has to be larger than multiples of skin depth at the particular frequency of interest.

So briefly with respect to the second scenario, the skin depth becomes relevant when we speak about shielding from electromagnetic waves rather than discharge current.

The first and the second scenarios can be put together in frequency spectrum, the first scenario describes why the cage protects current in low frequencies while the second scenario describes why it protects from both current and radiation at high frequencies.

I think the cage in the picture shows scenario 1. You can clearly see the distant electrodes and the point at which the spark hits the cage

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There will be some voltage built up accross a Faraday cage when there is current thru it. That's just from basic Ohm's law. However, the Faraday cage is ideally constructed with material that has low resistivity, and it's usually arranged in a mesh. You can think of each individual wire in the mesh as being a small resistor. Since the value of these resistors is very small to begin with, and there are many effectively in paralell from one end of the cage to the other, the end to end resistance of the cage is quite small.

Let's say that end to end a Faraday cage has a resistance of 100 mΩ. Even if a jolt of 100 A are running thru it, that will only create a potential of 10 V end to end. The human inside is still quite safe with 10 V accross the cage.

Note also that in the picture he is not touching any of the cage other than standing on the bottom, probably with shoes that provide some insulation. I'm not volunteering to do this, but even a few thousand volts difference between the top and bottom of the cage in that picture isn't going to hurt the person inside. It would take a lot more than that to break down the air between the top of the cage and the person's head.

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Here is a video where a person inside the cage is touching the inside (at minute 4:48): deutsches-museum.de/de/ausstellungen/energie/starkstromtechnik/… –  Julia Feb 15 '14 at 9:57
So you support the basic point of view, I cited in my question: "Some people say that the fact that the man inside the cage is safe doesn't have to do anything with faradays cage, it's simply because the the cage is a better conductor." However the explanation I heared most often is an argument, which shows in the static case (without any currents), that the field inside the cage is zero. Then it is concluded (without discussing that now a current appears) that the man in the cage is in the demonstration like on the picture in my question is safe. –  Julia Feb 15 '14 at 10:01
So I understand your basic argument, that's clear. But I don't understand why this should not be the whole explanation. I also understand why the field in the static case is zero inside the cage. But I don't understand why this also applies when a current (for example in the case of lighting like in the picture in my question) is flowing. I also don't understand how this relates to the fact that the man in the cage is safe and how it ralates to your basic explanation. –  Julia Feb 15 '14 at 10:04
Last but not least I don't understand why the skin effekt is cited sometimes in this context and how this relates to the other explanations. So would be great if you could add some details about those points. –  Julia Feb 15 '14 at 10:05

Actually, it does only against weak fields. Only against weak. And only against fields (E, B).

In short, It works because metals have many "fast electrons". These electrons have good reactions with phonons (thermal conductivity) and radiation photons (electromagnetic field).

There is current explanation in Maxwell Equations terms. Field generates current - current generates field with exact opposite sign and they compensate inside cage.

But, as radiation density grows, metal is evaporating and cage is destroyed.

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Experiments demonstrate that an electric charge will not pass through a metal ball, but pass about the surface.

Faraday suits has been worn by electricians while working on live wires. They touched the suit.

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This does not answer the question. –  ACuriousMind Mar 4 at 21:50
Electronic states are not clearly defined by standard theory.The formation of compressed dark matter, requiring energy, contains the like-charged particles. Think of spires that form before lightning strikes. –  Michael Mar 5 at 3:14