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There are systems that collect sun light in one spot.

enter image description here

I wonder, why does it accumulate additively, without destructive interference?

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-1 for "500 GW/hours Annual". Huh, what? We do science here. –  Olin Lathrop Jan 21 at 18:45
    
@OlinLathrop Alternative energy is largely a hype, I believe. Its purpose is to keep people asleep regarding the oil depletion and global warming so that people would buy more cars and build more urban sprawls. It are supposed to be stupid consumers and alternative energy is fine to keep them sleeping. So, the first image that google retreives, seems to serve this purpose very well. –  Val Jan 21 at 19:55

4 Answers 4

Let's suppose the light from the Sun was perfectly coherent. In that case you would get interference, however the optics used in the sort of solar tower you show are manufactured to nowhere near single wavelength of light precision. That means the phase of the light arriving at the collector would vary wildly with position across the collector, and the resulting interference pattern would be a speckle. At some points in the speckle destructive interference would make the intensity zero, but at others constructive interference would increase the intensity. The end result is that on average the intensity of the light would be the same as if no interference had occurred. Which makes sense, because the light energy flowing into the collector has to go somewhere. Remember, interference doesn't negate the energy coming in - it just moves it around e.g. by concentrating it into spots.

All of which is beside the point, because sunlight is not coherent, or at least not very coherent, so you aren't going to get interference and you won't get a speckle pattern. Just a patch of uniformly bright light.

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Yes, that is beside the point. The light is random and at some places you get 0 field, in the others duple field. So, net no field increase and, thus no energy summation. Are mirrors additive? –  Val Jan 21 at 17:54
    
@JohnRennie: "you aren't going to get interference and you won't get a speckle pattern. Just a patch of uniformly bright light": Watch the video in this question, we will not get a patch of uniformly bright light from the sun being used as a source for interference. –  Godparticle Jan 21 at 18:57
    
@VINAY: that experiment passes the sunlight through a pinhole to make it coherent. –  John Rennie Jan 21 at 19:57
    
@Val: the light from the different sources is always additive i.e. you add the electric fields to calculate the total electric field then square it to get the energy flux. With incoherent sources the flux fluctuates on time scales comparable to the period of the light, so on longer timescales the intensity averages to a constant value. Only for coherent sources do you get the flux difference persisting for long timescales i.e. a visible interference pattern. –  John Rennie Jan 22 at 9:58
    
This is what wonders me and this is what I ask about. How is this possible? You add multiple independent (you may add identically distributed) noises and get non-zero in the sum. Might be you can refer me to the branch of probability theory which says that average electric field is 0 but power (and, thus, electric field) is not because power and electric power is not simple average but is something else, e.g. it can be a variance, since it integrates the squares of the deviation? –  Val Jan 22 at 13:34

Short answer: On something operating with non-coherent light on the scale of a solar power collector, there is no net effect from interference. The increase in light intensity is not additive interference at all, but is simply that the light falling on a wide area is collected and focussed on a small area.

However, I'm guessing that there is some confusion on why interference doesn't seem to occur with sunlight. To understand what's going on here, let's ignore the solar power system, mirrors, etc., for a minute, and just think about the light that's arriving. Consider it as a lot of "parcels" of light.

If the sun were a laser, then the light from it would be "coherent" - i.e. the parcels would all have their peaks and troughs lined up with each other. If I were to hold my hand out to catch the light, the only thing that determined whether my hand intercepted a peak or a trough would be the distance that the light had travelled. However, the sun is not a laser, and so these parcels of light arrive out of phase with each other. If I hold my hand out to catch the light, no matter how far the light has travelled, I will catch some peaks, some troughs, and some in the middle.

Now consider a system with multiple beams that are joined in one point - such as the solar tower that you are interested in.

If the sun were a laser, then the different beams would have travelled slightly different distances, and so would arrive at different points in their waveforms, and so you would see an interference pattern: In one spot all the peaks line up, in another spot they cancel out, etc. This works because the light is coherent in the first place.

But as the sun is not a laser, the light is not coherent and there is a jumble of different phases arriving at the same time. Some of these will interfere with one another: but some will be constructive, and some will be destructive, at random. When you average it out over a large number of parcels of light, there is no overall effect from interference.

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Well I thought John Rennie explained it as well as is needed.

The sun IS NOT a point source, or anything like one, since we can make highly detailed images of it even here on earth. So to talk about coherence, is absurd. It isn't spatially coherent from point to point over the image, and it isn't even temporally coherent for any diffraction limited image point.

So you will never see any interference effects on a boiler receiving surface.

And as John pointed out, the energy doesn't disappear in a real interference situation anyway.

Why do people think everything is a laser ?

And those mirrors used for thermal solar energy of the kind depicted, are not high finesse optics. They will work just fine, even if they are quite flat, because, if you made them paraboloidal, they have to have an enormous focal length so the f/number of each mirror is extremely small. It's cheaper to make them all flat, or else each one has to have a different spherical curvature. They might be slightly curved for surface stability; but they hardly need to be.

And yes the mirrors are totally additive, and each one has to be individually steered to track the sun.

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The question is why do people speak about source coherence when I ask about coherence of the received waves? I ask you how do you achieve the additivity out of incoherent source. Why do you discuss the incoherence of the sun rays? –  Val Jan 22 at 8:05

When one is talking of energy, it is simpler to think "photons", because each photon carries an energy h*nu. When it hits a material the energy of each individual photon as it impinges on matter is finally totally absorbed by the material of the target, either turning into electricity or heat. In the photon quantum mechanical framework it is evident that destructive interference is not in the game. h*nu never disappears. (Even with coherent beams that show interference patterns this is true, the energy is displaced but does not disappear).

Now the classical electromagnetic wave emerges naturally from the underlying quantum mechanical stratum, and the result is the same. White light is composed of many frequencies, each frequency will have its own average electric field whose square is proportional to the energy density carried by the frequency. Integrating over all the average electric fields cannot become 0 in any part of space and time because the waves come incoherently and even if focused on a small area they are out of phase in space and time and an integral over the average energy in each frequency holds .

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