# What is so special about speed of light in vacuum?

I will try to be as explanatory as possible with my question. Please also note that I have done my share of googling and I am looking for simple language preferable with some example so that I can get some insight in this subject.

My question is what is so special about $c$? Why only $c$. Its like chicken and egg puzzle for me. Does Einstein reached to $c$ observing light or does he got to light using some number which turned out equal to $c$.

Why is $c$ not relative. If something has zero rest mass like a photon why they only travel at $c$ in vacuum and not with $c+1$ or $c-1$?

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See my answer here, where one can show by symmetry arguments that a fundamental speed limit $c$ exists (possibly infinite). From there, it's a matter of experimental testing to find something with the behavior foretold by these symmetry arguments. The Michelson Morley experiment found that the speed of light had this special behavior. See John Rennie's answer too. There are many ways to look at this. – WetSavannaAnimal aka Rod Vance Oct 11 '13 at 9:02
– Ben Crowell Oct 11 '13 at 20:00
why using the "infinite" word ? we know that c is about 3*10^8 km/s, so its not infinite. and it is verifiable everyday in telecommunications (lag). – v.oddou Jan 10 '14 at 3:44

Special Relativity is based on the invariance of a quantity called the proper time, $\tau$, which is the time measured by a freely moving (i.e. not accelerated) observer. The proper time is defined by:

$$c^2d\tau^2 = c^2dt^2 - dx^2 - dy^2 - dz^2$$

This is similar to Pythagoras' theorem as learned by generations of schoolchildren, except that it includes time (converted to a distance by multiplying by $c$) and it has a mixture of plus and minus signs. The mixture of signs is responsible for all the weird effects like time dilation and length contraction, and because there is a mixture of signs the value of $d\tau^2$ can be positive, negative or zero.

If $d\tau^2$ is less than zero then $d\tau$ must be imaginary, and therefore unphysical. A quick bit of maths will show you that $d\tau^2$ can only be negative if you travel faster than light, and therefore that $c$ is the fastest speed anything in the universe can travel.

So $c$ is special because it determines a fundamental symmetry of the universe.

Footnote:

I've said $c$ is special while Kostya has said the opposite, but actually we are both right.

Kostya is right that there is nothing special about the speed 299,792,458 m/s (though if you change it by much you'll change physics enough that we may not be here :-). However the speed at which light travels is very special because anything travelling at this speed follows a null geodesic, i.e. $d\tau^2 = 0$. This is the sense in I mean that $c$ is special.

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+1 Let me offset that drive-by, though I actually wonder why you don't mention the Michelson-Morley experiment which (unless I'm wrong) made people try to get their heads around the speed of light being observer-invariant, thus leading to that concept of proper time. (not to mention some Einstein thought-experiments) – Mike Dunlavey Oct 11 '13 at 20:18
This is not an answer to the question. Here you have simply verified that c is special. Via bringing Special Relativity into the picture, you have stated that c determines a fundamental symmetry of the universe, rather than have been stating exactly what it is that determines its ability to determine a fundamental symmetry of the universe. Concerning "Why is c not relative?", one must not just reveal the bizarre outcomes of c not being relative, but one must reveal instead, why it is that c is not relative. Circular or back stepping logic, will not, and does not, provide an absolute answer. – Sean Nov 29 '14 at 22:16
@JohnRennie ... the value of $dτ^2$ can be positive, negative or zero." Can it? The similarity of the equation to Pythagoras Theorem is not accidental. The rhs of the equation comes from this equation: $c^2dt^2=dx^2+dy^2+dz^2$, which is the path of light in a 3D space. Therefore $c^2dt^2$ can never be less or more than $dx^2+dy^2+dz^2$, which means that the rhs of the equation for proper time is always zero. As the equation was derived for light, so the speed must be limited to $c$ by definition. – bright magus Dec 3 '14 at 13:54

Nothing. From Nature's perspective speed of light is entirely artificial number.

Imagine that you've discovered an alien culture that measured horizontal length $\ell$ and height $h$ in different units. They live on a planet with very strong gravitational force, and for them it is very difficult to rotate stuff in vertical plane. Such kind of rotations are really unnatural and counter-intuitive for alien-layman. While alien-physicists discovered them and have introduced a special transition coefficient $\alpha$ that transformed one dimension into another, allowing aliens to understand that both of these quantities are just projections of a more general thing called "distance": $$d^2 = \alpha^2 h^2 + \ell^2$$

Then imagine that there is an alien-physics.stackexchange site and someone asked there "What is so special about that $\alpha$?" And the answer is, again, "nothing". Nothing is special about $\alpha$ -- these aliens are just used to special conditions.

Same thing applies to homo sapience -- we are just used to very low speeds, which makes us think that time and space are completely unrelated and cannot be "rotated" into each other. While non-alien-physicists discovered that this is not the case, introducing a transition coefficient $c$...

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I really like your alien analogy, but I think one could take the conclusion to be that there is actually something very special about $\alpha$. It's the most (in fact the only) "natural" way of converting height into an equivalent horizontal length. It also corresponds to the angle $45^\circ$, which is arguably a special angle in the sense that it contains equal components vertical and horizontal. So I'd say there is some flexibility of interpretation here. – David Z Oct 11 '13 at 18:50
Hmm... Were you mentioning "Homo sapiens" (at the end), or intentionally mentioned "sapience"? ;-) – Waffle's Crazy Peanut Oct 13 '13 at 3:49
@CrazyBuddy pun intended... – Kostya Oct 13 '13 at 10:35

Einstein in 1905 derived $c$ from the Maxwell's equations. Exact title of the paper in which special relativity was published was On the Electrodynamics of Moving Bodies. He essentially just resolved the problem of two electrons moving relative to each other. Moving electrons create a changing magnetic field and at the same time they are accelerated by Lorentz force and electrical force originating from the field.

In an inertial frame of reference associated with any electron there is no magnetic force ($q\mathbf{v}\times\mathbf{B}$, $\mathbf{v}$ being $\mathbf{0}$), only electric field acts on the electron. The solution is: if we change our frame of reference to a frame of reference which is moving at constant speed there is a transfer between magnetic and electric fields. There inherently is a constant in the transformation which units are metres per second. It was called "an Einstein's constant".

Einstein looked at speed of electromagnetic waves calculated using well known at the time magnetic and electric constants (the same formula as for Einstein's constant, by the way), and noted that resemblance with observed speed of light is... intriguing. It was just a suggestion of light being an electromagnetic wave.

So:

• Einstein's constant
• speed of light

two separate things. But since light is an electromagnetic wave, it's speed in vacuum is equal to Einstein's constant $c$.

Today commonly we call it just "speed of light" for convenience, but in many contexts it could be called "Einstein's constant".

$$c = \sqrt{\frac{1}{\epsilon_0\mu_0}}$$

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$c$ was derived not by Einstein, but by Maxwell. So, it's rather Maxwell's constant. – Ruslan Aug 19 '14 at 7:17
$c$ as in electromagnetic field transformation - Einstein. $c$ as in speed of electromagnetic wave - Maxwell. Both are mathematically equal, so one symbol $c$ is used. – user2622016 Feb 18 at 9:10
Electromagnetic field transformation was first derived by Lorentz, hence their name — not by Einstein. – Ruslan Feb 18 at 13:14
Lorenz transformation is something different, it is transformation of spacetime, not transformation of electric and magnetic fields. The main Einsteins question was how two moving electrons repel or attract each other. To get an answer we need to transform electric and magnetic fields to other frame of reference. Einstein calculated it in 1905. – user2622016 Feb 18 at 13:31
Lorentz transformation is not limited to world points, it's the transformation for all the 4-vectors and 4-tensors, including 4-potential $A^\mu$ and EM tensor $F^{\mu\nu}$. Although you may be right that it's Einstein who found transformations for $E_i$ and $B_i$, I don't know this for sure. – Ruslan Feb 18 at 14:47

Well one way of looking at it is as follows.

Imagine that we exist within a 4 dimensional environment, a Space-Time environment. Now imagine that we have an object that extends across space and that this object is at rest in Space. However, this object is still in motion. It is still in motion across one of those 4 dimensions. It is in motion across the dimension that is known as the dimension of time.

Now imagine that the magnitude of this motion is equivalent to the speed of which light moves across space (c), and that this specific (c)onstant motion applies to all objects.

No matter what direction any of the objects travel within Space-Time, this specific magnitude of motion is maintained. If a bus turns at a corner, the bus has changed its direction of travel, and thus in turn the bus has rotated. Thus, if any object, as it moves across Space-Time, changes its direction of travel, here too, rotation occurs.

Now, if you take all of this into account and analyze the outcome of such circumstances, you encounter Length contraction, Time dilation, Lorentz Transformation equations, the Velocity addition equation, and the relativity of Simultaneity.

You also find that under such circumstances you will measure the speed of light as c, and do so no matter what frame of reference the light is being measured from, nor does it matter which direction the light is traveling toward.

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This could be the best visual explanation of my question and it's answer: https://www.youtube.com/watch?v=IXxZRZxafEQ

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