A particle A decays into particles B, C and D. The spin of A, B and C particles is 1/2 each. What are the possible spins of particle D?
My attempt is the following:
Since B and C have spin 1/2 each, these can form singlet or a triplet. So the spin of D can only be 1/2 to get a spin of 1/2 for the decayed particle A. But the correct answer which is given is that D can have values like 1/2, 3/2, 5/2, 7/2.... Can any enlightened expert in Physics explain this please. his reaction looks like the decay of a neutron(A) into proton(B), electron(C) and anti-neutrino(D). So I believe my answer to be correct because neutrino has spin=1/2. I would still like confirmation of my reasoning from others.