Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

Specific heat of nano particles is less than bulk specific heat of them. Why?

share|improve this question

1 Answer 1

up vote 2 down vote accepted

The specific heat of the bulk is the integral of the specific of all the applicable energy carriers. Let us consider electrons and phonons for simplicity

$$ C_{v-total} = C_{v-electrons} + C_{v-phonons} = (\frac{\partial U}{\partial T}_{v-electrons}) + (\frac{\partial U}{\partial T}_{v-phonons})$$.

Taking into account that energy distributions, we can calculate the specific heat as $$ C_{v-total} =\frac{d}{dT}\int E f_{FD}(E)D(E)dE + \frac{d}{dT}\int E f_{BE}(E)D(E)dE $$

Where the distributions are the fermi-dirac and the Bose-Einstein distribution. Obvioulsy, when you have a bulk material, like a solid, the density of states is modified to accommodate the overalap of the electronic states resulting in band formation. This does not happen in free particls (nano-particles e.g).

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.