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A popular assumption about black holes is that their gravity grows beyond any limit so it beats all repulsive forces and the matter collapses into a singularity.

Is there any evidence for this assumption? Why can't some black holes be just bigger neutron stars with bigger gravity with no substantial difference except for preventing light to escape?

And if neutrons collapse, can they transform into some denser matter (like quark-gluon plasma) with strong interaction powerful enough to stop the gravity?

In this video stars are approaching supermassive black hole in the center of our galaxy in a fraction of parsec. The tidal force should tear them apart, but it doesn't. Can there be some kind of repulsive force creating limits for attractive forces?

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migrated from skeptics.stackexchange.com Aug 29 '13 at 12:31

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The stars in the center of galaxy do not orbit in a fraction of a second. These orbits were created from pictures taken over 15+ years. They are not live videos. The stars indeed go very fast but the orbit itself takes years. –  physics1 Aug 29 '13 at 15:21
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@physics1 he said parsec, not second. –  Kyle Aug 29 '13 at 18:16
    
@Kyle thx for clarification. –  physics1 Aug 29 '13 at 18:18
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duplicate or near duplicate of physics.stackexchange.com/q/18981 –  Ben Crowell Aug 29 '13 at 22:29
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related: physics.stackexchange.com/q/44990 –  Ben Crowell Aug 29 '13 at 23:14

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A popular assumption about black holes is that their gravity grows beyond any limit so it beats all repulsive forces and the matter collapses into a singularity. [...] Is there any evidence for this assumption?

It's not an assumption, it's a calculation plus a theorem, the Penrose singularity theorem.

The calculation is the Tolman-Oppenheimer-Volkoff limit on the mass of a neutron star, which is about 1.5 to 3 solar masses. There is quite a big range of uncertainty because of uncertainties about the nuclear physics involved under these extreme conditions, but it's not really in doubt that there is such a limit and that it's in this neighborhood. It's conceivable that there are stable objects that are more compact than a neutron star but are not black holes. There are various speculative ideas -- black stars, gravastars, quark stars, boson stars, Q-balls, and electroweak stars. However, all of these forms of matter would also have some limiting mass before they would collapse as well, and observational evidence is that stars with masses of about 3-20 solar masses really do collapse to the point where they can't be any stable form of matter.

The Penrose singularity theorem says that once an object collapses past a certain point, a singularity has to form. Technically, it says that if you have something called a trapped lightlike surface, there has to be a singularity somewhere in the spacetime. This theorem is important because mass limits like the Tolman-Oppenheimer-Volkoff limit assume static equilibrium. In a dynamical system like a globular cluster, the generic situation in Newtonian gravity is that things don't collapse in the center. They tend to swing past, the same way a comet swings past the sun, and in fact there is an angular momentum barrier that makes collapse to a point impossible. The Penrose singularity theorem tells us that general relativity behaves qualitatively differently from Newtonian gravity for strong gravitational fields, and collapse to a singularity is in some sense a generic outcome. The singularity theorem also tells us that we can't just keep on discovering more and more dense forms of stable matter; beyond a certain density, a trapped lightlike surface forms, and then it's guaranteed to form a singularity.

Why can't some black holes be just bigger neutron stars with bigger gravity with no substantial difference except for preventing light to escape?

This question amounts to asking why we can't have a black-hole event horizon without a singularity. This is ruled out by the black hole no-hair theorems, assuming that the resulting system settles down at some point (technically the assumption is that the spacetime is stationary). Basically, the no-hair theorems say that if an object has a certain type of event horizon, and if it's settled down, it has to be a black hole, and can differ from other black holes in only three ways: its mass, angular momentum, and electric charge. These well-classified types all have singularities.

Of course these theorems are proved within general relativity. In a theory of quantum gravity, probably something else happens when the collapse reaches the Planck scale.

Observationally, we see objects such as Sagittarius A* that don't emit their own light, have big masses, and are far too compact to be any stable form of matter with that mass. This strongly supports the validity of the above calculations and theorems. Even stronger support will come if we can directly image Sagittarius A* with enough magnification to resolve its event horizon. This may happen within 10 years or so.

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This answer could be improved with a bit more information on how these theorems support the idea of a singularity. As it stands the answer just refutes the question by naming an unelaborated-on theorem. –  KennyPeanuts Aug 29 '13 at 19:29
    
@KennyPeanuts: Good comment, thanks. I wrote the original version in a hurry. I've expanded on it now. –  Ben Crowell Aug 29 '13 at 21:14
    
I found there are already some links on Physics.SE to descriptions of the theorum: including physics.stackexchange.com/questions/60869/… and the first lecture of arxiv.org/abs/hep-th/9409195 –  ChrisW Aug 29 '13 at 21:15
    
@KennyPeanuts: the theorems would be very, very technical to someone who doesn't already know basic general relativity. If you want more than what is elaborated on here, it would be best to ask a separate question –  Jerry Schirmer Aug 29 '13 at 22:03
    
@JerrySchirmer: I've tried to give a brief and nontechnical explanation of what each theorem means. –  Ben Crowell Aug 29 '13 at 22:16

The final stages of star collapse include various stages, but three common ones to consider are white dwarfs, neutron stars, and black holes.

White Dwarfs are formed when gravitational forces of the mass of the remnants of the star cannot overcome the repulsion of the electron degeneracy pressure. So think of gravity competing with the electromagnetic force, but the latter wins, so further collapse doesn't happen.

Neutron Stars are formed when the gravitational forces overcome the repulsion of electron degeneracy pressure, but are now stopped by the force between neutrons. This is called quantum degeneracy pressure is results from the Pauli Exclusion Principle. Once this force is overcome from sufficient gravity, it's possible that there is another phase, the quark star, where quarks exert an outward pressure. But there's a limit to this pressure too. We can keep adding matter practically forever, so no matter what kind of outward pressure gravity is faced with, eventually it can always overcome it. From all of the known types of forces, there is always a case where gravity can overcome the strongest repulsive forces. That is why physicists believe it must collapse into a black hole. However, this could turn out to be false if we are missing a chunk of physics that somehow tells us there is a brand new force and it changes all of physics! This is unlikely though. Hope that helps.

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Black holes do not have singularities. Since all matter of a black hole is located in its spherical shell, the internal spacetime is flat.

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What makes you think that all matter is in a spherical shell? –  MBN Jan 15 at 12:11
    
@MBN if some matter was inside the spherical shell, there would be information loss paradox. Also, this would allow to send signals from the inside, say by placing the matter differently so to create non-spherical gravitational field or changing the BH rotation speed. –  Anixx Jan 15 at 12:28
    
But there is or was matter inside, otherwise what happens to the star that collapses to a black hole? –  MBN Jan 15 at 18:30

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