# container with low pressure inside of the high pressure container [closed]

How will act low pressure container, or what would happen inside the low pressure container when it is placed inside the container with high pressure?

And if it is high pressure container inside the high pressure container? Will the container which is inside stay in the centre?

-

## closed as unclear what you're asking by John Rennie, Emilio Pisanty, Dilaton, Waffle's Crazy Peanut, akhmeteliAug 23 '13 at 17:32

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question.If this question can be reworded to fit the rules in the help center, please edit the question.

Why do you think it should stay in the center? – Ali Aug 22 '13 at 8:47
ok, no matter what I will say you already mark this as wrong – d689p Aug 22 '13 at 9:35
probably because placing equal high pressure on high pressure would give a total of 1 or 0, that means the object would stay on its place, as there would be a magnetic field and we are on earth(atom would stay in the centre), the object will stay in the centre. – d689p Aug 22 '13 at 9:38

About the position of the inner container: it will fall as everything, except in the case that the buoyancy is stronger than the weight of the container: $$F_{buoyancy}=V(\rho_{out}-\rho_{in})g>m_{container}g=F_{weight}$$