# Second quantization with qubits

Is "second quantization" means system wich can contain variable, unknown, superposed and otherwise uncertain number of qubits?

Can "second quantized" system contain 0.5% of 1 qubit and 95% of 2 qubits?

Does this mean that quantum field state cannot be described with quantum computer with fixed number of qubits?

Or may be this is wrong and the "power" of qubit is sufficient?

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In Fourier modes, states can be represented by creation operators, labelled by momentum and polarization, acting on vacuum. So, you can write a state like : $|\Phi> = 0.005~a~^+(\vec k, \lambda)|0\rangle + 0.95~a^+(\vec {k'}, \lambda')~a^+(\vec {k''}, \lambda'')|0\rangle$ that is : $|\Phi> = 0.005~|\vec k, \lambda\rangle + 0.95~|k', \lambda', k", \lambda"\rangle$ A state like $|k', \lambda', k", \lambda"\rangle$ is automatically symmetrical for bosonic fields and antisymmetrical for fermionic fields, because of the properties of the creation operators. – Trimok Aug 17 '13 at 17:31