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I've read several websites about equipment covered with gold foil and astronaut helmet visors are coated with gold. However, their explanations are devoid of almost all physics content. Can someone explain the basic concept of why gold foil is so popular with NASA as a coating on visors?

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In space, the sun transfers heat via radiation to equipment and astronauts. Although the sun’s peak emission is in the visible region (about 500 nm), you can see that there is also a fair amount IR (infrared) and UV (ultraviolet) emitted as well at the top of the atmosphere.

enter image description here

To control the surface temperature of an object that is exposed to IR (heat waves), NASA wraps its equipment with a metallic reflector that reflects IR to keep it from getting “hot.” The common reflectors are aluminum, silver, copper and gold. Below, the plot of reflectance vs. wavelength shows that all four metals are good IR-reflectors since the reflectance is close to 100% for wavelengths greater than 700 nm (λ ≥ 700 nm).

enter image description here

So why use gold? It’s most likely the same reason why they use gold extensively in circuit boards. (i) Gold does not corrode or rust while silver and copper does, which would reduce reflectance (by the way this happens before takeoff) and (ii) it’s a lot easier to work with gold than aluminum.

The outer sun visor is made from a polycarbonate plastic and coated with a thin layer of gold. This combination gives complete protection to the astronaut. Why? Your eyes can focus both visible and near IR light onto your retina equally well. Your eye has visible receptors but not IR ones. When intense visible light hits these receptors, the receptors transmit information letting you know that this is painful and will cause damage if you don’t either close them or look away. On the other hand, without IR receptors, you wouldn’t realize that your eye was being “burned” with an intense IR source. Therefore, astronauts need IR protection from intense sunlight above the earth atmosphere. From the plot above, using a gold-coated visor reflects almost all IR but gold will also transmit about 60% of visible as well as UV light for about λ ≤ 500 nm. According to the plot above, with the visor down you would see a blue-green hue to objects). On the other hand, about 60% of UV is transmitted through the gold but a polycarbonate plastic visor has excellent visible transmittance but absorbs/reflects almost all UV as shown below.

enter image description here

PMMA (Polymethylmetacrylate, Lexan, Plexyglass..) and PC (Polycarbonate, the DVD material)

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Your answer is thorough and well worded. I got all the physics and understood it better after reading this. Much appreciated! –  Smith Aug 17 '13 at 16:58
8  
There's another reason that is presented clearly in Figure 2: gold reflects significantly less visible light than the other metals, yet it reflects a comparable percentage of IR. –  Miles Erickson Aug 17 '13 at 17:42
    
@Smith: that is a pretty generous remark. I've learned a lot from this website and continue doing so, so keep posting. It's a benefit to all of us! –  Carlos Aug 17 '13 at 18:49
    
@Miles: nicely put. –  Carlos Aug 17 '13 at 18:50
    
I know this post is old, but they also use gold because it is a stable and dense element. Many of the instruments are exposed to heavy radiation doses and the last thing electrical engineers want is a radiation source hitting their circuit boards. Gold and tungsten are great for blocking particle and UV radiation in many cases (actually, they use layers of tungsten, aluminum, and other metals which actually works better than a thick layer of one metal). –  honeste_vivere Jul 1 at 11:09

protected by ACuriousMind Feb 11 at 23:45

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