Is it possible to have a geostationary satellite over the poles?

My understanding of orbital mechanics is very limited, but as I understand geostationary satellite, they stay in place by having an orbital speed corresponding to the spot they're orbiting over.

So my basic intuition tells me that it's not possible to have a geostationary satellite over the poles, since they're effectively standing still, and to my knowledge, a satellite must keep a certain velocity to keep from getting pulled down by gravity.

Am I missing something?

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Why the close-vote? This is a perfectly valid, well-phrased question. – Emilio Pisanty Jul 19 '13 at 14:53

There cannot be a geostationary satellite at the poles, basically because it would have to be at rest, which cannot happen as it would get pulled by the earth's gravity and eventually crash to the surface.

In fact, there cannot be a geostationary satellite anywhere else, except above the equator(in an equatorial orbit). This is fairly easy to prove.

Imagine that you wanted a satellite directly above the place where you are right now, lets say 500 km away. Now we know that the earth is rotating, so the place 500 km directly above you will also move in a circle.This circle has its center somewhere on the rotational axis of the earth(Not necessarily coinciding with the center of the earth).

If you want your satellite to move on that path, It will require a centripetal force continuously acting towards that center. Now if a satellite is purely under the influence of earth's gravity, there is a force acting on it directed towards the earth's center. Now if this force were to act as the centripetal force for the motion we want for our satellite, the orbit's center would have to coincide with the earth's center, leading us to the fact that a geostationary orbit has to necessarily be an equatorial orbit!

P.S. I'm sorry I couldn't provide you with a 3D diagram, but Wikipedia has a great diagram for a geostationary orbit:

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You used cetrifugal in the first sentence of your second-to-last paragraph, where I assumed you meant centripetal. I also added the image I think you wanted. – Colin McFaul Jul 19 '13 at 15:02
@ColinMcFaul, thanks I didn't see that mistake. I actually wanted another image, one in which the satellite is not revolving on an equatorial axis but elsewhere. – udiboy1209 Jul 19 '13 at 16:30
Non-equatorial satellites would've to cover a cone shaped orbit with Earth. Being 3D, it is rearranged back to 2D by angular momentum conservation. – Renae Lider Mar 10 '14 at 7:32

For a satellite to orbit around the earth, we need to ensure the following: (a) Satellites orbital plane must pass through the center of the earth (b) It must have sufficient CPF centripetal force, to continue on its orbit without getting pulled into by the gravity of the earth (c) At a constant orbital speed the satellite must cover same length of the track per unit time, if traced on the earth surface and all this is possible only if the satellite is placed in an orbit exactly over the extended space over the equator.... and no where else.

Geosynchronous... orbits also have one sidereal time per orbit but they are not stationary they describe a path called " analemma" equal to figure of alongated 8.////

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The accepted answer by udiboy is completely right; however theoretically it is not only gravity that acts on a satellite, but also light pressure from the Sun and Earth. Given a sufficiently light and large solar sail (implausible at the current technological level), it is possible to counteract acceleration due to gravity and enter a totally non-Keplerian orbit above one of the poles. This way the (mega) satellite will always stay illuminated.

For the displaced GSO in the figure above (numbers from Vulpetti et al. book of 2008, p.214):

• Sailcraft elevation at North Pole: 11 degrees (not perfect, but acceptable in fair weather)
• Orbit displacement ($Z$): $2.211 R_{Earth}$
• Orbit radius ($\rho$): $6.2300 R_{Earth}$
• Sail distance ($r$): $6.6107 R_{Earth}$
• Lightness numbers: $\lambda_{Sun} = 12.65 ; \lambda_{Earth} = 0.334$
• Sailcraft sail loading (mass/usable sail area): $\sigma = 0.1215 \frac{g}{m^2}$

To put things in perspective, a perfectly reflecting sail at 1 AU from the Sun (i.e. near the Earth) gets $9 \frac{N}{km^2}$ from solar pressure (puny nine Newtons per sq.km of surface).

The practical value of such a satellite is limited:

• It will be difficult to maneuver (we haven't mastered attitude control for flexible rigs yet), and a sufficiently grave mistake will likely lead to a spectacular re-entry.
• At such a large scale it will contribute to global warming and Arctic/Antarctic ice melting.
• Payload will be minuscule. Basically, anything else than the sail will be a problem, so barring huge advances in nanotechnology there'll be no decent thermal control etc.

References

• Colin R McInnes. Solar sail mission applications for non-Keplerian orbits. Acta Astronautica V.45, no.4-9, 1999. Pp.567-575.
• Various books and articles by Vulpetti, Les Johnson, and McInnes.
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While near-future solar sail materials fall well short of what would be needed to maintain a permanent presence over a pole, offsets from geosynchronous orbit large enough to park an additional or ring of satellites north and south of the equator is plausible. Being able to put several times as many satellites in geosyncronousesque orbits would be a major benefit. – Dan Neely Jul 19 '13 at 17:19
I disagree with the impracticality. The farther out you put it the easier it is to do it, you can choose to make the task as easy as need be. Of course this runs up the lightspeed lag but for one-way transmission (say, TV broadcasts) that's not important. I do agree that a failed satellite falls out of the sky. – Loren Pechtel Jul 19 '13 at 17:31

To extend what others have written, the beauty of a satalite in a Clarke Orbit is that once you point your receiver at it, your receiver can stay put. Great for telecommunications.

A satellite in a polar orbit on the other hand, will pass over the entire surface of the Earth in a few orbits. It goes pole-to-pole as the Earth turns under it. Great for spy satellites and geological surveys.

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This does extend what others have said, but doesn't actually answer the question as asked. Might be better as an edit to another answer or a comment? – Kyle Oman Jul 19 '13 at 19:58
Perhaps, but I can't add an animated gif to a comment. – user27279 Jul 19 '13 at 20:07
That's why I suggested edit (or you ca link in a comment, or expand your answer to actually answer the question). – Kyle Oman Jul 19 '13 at 20:32

As noted you can't be stationary without a really big solar sail or magic rockets. The usual solution to this problem are orbits with long hang times in view of a pole, specifically the Molniya orbit, commonly used by the Russians with a lot of high-latitude territory. Multiple Molniya satellites can provide very good coverage.

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Sirius Satellite radio uses a similar orbit, to get better "hang time" over North America. – Mark Bessey Jul 19 '13 at 19:22
Plus one for bring up Molniya orbit. – Asphir Dom Jul 20 '13 at 12:08

protected by Qmechanic♦Jul 13 '14 at 9:20

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