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Why an electron "rotate" around the nucleus at a speed close to the light one? I mean where he gets all this energy? One DOES NOT simply approach the speed of light AFAIK.

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closed as unclear what you're asking by Waffle's Crazy Peanut, Dilaton, Qmechanic Jul 11 '13 at 12:32

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question.If this question can be reworded to fit the rules in the help center, please edit the question.

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Who said that it does? Non-relativistic QM describes light elements very well. –  Chris White Jul 10 '13 at 23:36
    
I close this question as unclear what you're asking, but the question is really closed because it rests on a false premise. In other words, in order to re-open this question, OP (or somebody else?) should add a published reference that backs up his premise. –  Qmechanic Jul 11 '13 at 12:39

1 Answer 1

(1) if it were a classical system, the correct word is "revolve" rather than "rotate"; the Earth rotates every 24 hours and revolves around the sun (approximately) every 365 days

(2) since it's not a classical system, the notion of an electron revolving around the nucleus is suspect. Indeed, for S orbitals, the orbital angular momentum is zero.

So, where do you get this notion that your question is based on?

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That's why I put " around rotate. I don't remember where I have read it... –  Hakim Jul 11 '13 at 0:19
    
@حكيمالفيلسوفالضائع, perhaps some more research is in order then? –  Alfred Centauri Jul 11 '13 at 0:37
    
Of course taking the Fourier transform of the position distribution yields a momentum distribution from which you can determine if the semi-classical approximation is adequate to your needs. –  dmckee Jul 11 '13 at 1:28

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