# How occurs the enantiomorph of the mirror? [duplicate]

How occurs the enantiomorph of the mirror?

I would like to know how occurs the RELATIONS OF THE RAYS with the mirror and the image, everything that happens to be flipped image from the right to the left.

-

## marked as duplicate by Dan, user1504, Qmechanic♦Jul 9 '13 at 17:48

This question was marked as an exact duplicate of an existing question.

Have you considered checking wikipedia for some basic definitions and formulas? Then you may come up with a more specific question. – Aziraphale Jul 9 '13 at 13:16
Duplicate? physics.stackexchange.com/q/8227, one of the highest rated questions on this site, so it has some excellent answers :) – Kyle Oman Jul 9 '13 at 13:25
That's good! Thank you for the link, I still need to learn how to find questions just like my question. – user73276 Jul 9 '13 at 13:29
I analyzed all the content of the link, but have not found a physical evidence with the rays. How it travels and all the physical explanation with the rays. – user73276 Jul 9 '13 at 13:42
@Kyle Non sequitur – babou Jul 9 '13 at 14:16

From the link in the comments it should be clear that a mirror does not flip left/right but rather in/out. The mirrored image is flipped at the (surprise!) mirror plane. If you look at the mirror at an angle $\alpha$, you are looking at something that has the same angle between the perpendicular and the point where the "looking-ray" hits the mirror. This is independent of the direction in which you are looking. The physical explanation of the rays can be reduced to: Incoming angle equals outgoing angle.