# dimensional regularization and the finite part

let be a dimensional regularized integral

$$\int d^{4-\epsilon}kF(k,m,s)= \frac{2}{\epsilon}+\frac{m^{2}}{3}(\gamma +log(4\pi)-\frac{1}{\epsilon}))$$

then formally if we elmiinate the divergent quantities we may have

$$\int d^{4-\epsilon}kF(k,m,s)_{reg}= \frac{m^{2}}{3}(\gamma +log(4\pi)+log\mu)$$

here 'm' and 's' are parameters and $\mu$ and energy scale

but is it that enoguh is renormalization simply 'deleting' teh divergent quantities proportional to $\frac{1}{\epsilon ^{k}}$ ??

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I'm not sure how you got your results, but renormalization isn't simply deleting the $\frac{1}{\epsilon}$ terms, we need to choose our counterterms such that they remove these divergences. –  Will Jul 3 '13 at 19:44