I am trying to figure out the amount of work done when I walk X miles or for X minutes. So I got Work=Force x Distance and Force=Mass x Acceleration and Acceleration=(change in velocity)/time. I am stuck at the acceleration part. As far as I am concerned my velocity is constant, so Acceleration=0 therefore Force and Work are 0. This doesn't seem right. What am I missing here?
|show 2 more comments|
When it comes to modeling the human body and its movements it becomes a lot more complex, because you actually have to model the different components of your body and how they attribute to the system. Plus you are not traveling at a perfectly constant velocity when walking at a steady pace.
If you were to model the work done by the human body while walking, you obviously will consider more of the lower body. I would personally neglect what the upper body does, even though your back muscles help move the legs and arms help stability and the respiratory system. However you want to know the quantity of work done by your legs, essentially.
Essentially (and crudely) it would be modeled by a set of joints that represent your legs and a block of mass M (your weight in total), and there it just a series of statics problems where you may model the movement of S number of steps and you can quantify the work done by your legs per step, and don't forget friction.
When we walk 3 forces act on us normal, gravitational and friction. For normal and gravitation force perpendicular to total displacement so by dot product rule work done is 0.and for static friction 0 displacement, when we displace we don't contact with ground so friction don't do any work.so over all work done in walking is 0.
protected by Qmechanic♦ Nov 1 at 10:26
This question is protected to prevent "thanks!", "me too!", or spam answers by new users. To answer it, you must have earned at least 10 reputation on this site.