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I am mathematician and have paper which models situation when homogeneous magnetic field is applied to moving electrically conducting fluid. There is such Lorentz force formula on which all the work is made:

$$F= \sigma (E + V \times B) \times B $$

But I think that the last $\times B$ is not needed. Is this correct formula for this case or the work is not correct?

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up vote 2 down vote accepted

Let us start by summarising the governing equations of MHD. We have the reduced form of the Maxwell equations

$$\nabla \times \mathbf{B} = \mu \mathbf{J},$$ $$\nabla . \mathbf{J} = 0,$$

$$\nabla \times \mathbf{E} = - \partial \mathbf{B} / \partial t,$$ $$\nabla.\mathbf{B} = 0$$

and the auxillary equations

$$\mathbf{J} = \sigma(\mathbf{E} + u \times \mathbf{B}),$$ $$\mathbf{F} = \mathbf{J} \times \mathbf{B}.$$

From the last two equations you get your result, namely that

$$\mathbf{F} = \sigma(\mathbf{E} + u \times \mathbf{B}) \times \mathbf{B}.$$

Note that the above combine to give the induction equation.

I hope this helps.

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Is it so I can't use the general formula of moving particle with charge mentioned in anyhow? Are these both formulas somehow related? Is this force of MHD also called "Lorentz force"? Thank you! – Gedrox May 30 '13 at 9:39
You cannot use the Lorentz force equation for particles, on fluids. So the short answer is no. This is due to the fact that plasmas are conducting fluids. The closest you can get to the Lorentz force law is to consider a fluid element of charge density $q$ and current density $\mathbf{j}$ then you can write the force per unit mass acting on that element as $\rho\mathbf{F} = q\mathbf{E} + \mathbf{j}\times\mathbf{B}$. No this is not commonly referred to as the 'Lorentz Force' as far as I am aware... – Killercam May 30 '13 at 9:59

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