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I'm a newbie with physics but I'm wondering how a ray of light can essentially be represented. I have always known that a ray of light proceeds in a straight line until it encounters another object (or material) that refracts/reflects it. But a light ray should be part of an electro-magnetic wave, is this correct? If it is so, it should obey to the wave equation and this doesn't seem to me to describe a straight line ray.

I'm having problems visualizing how light is emitted and how it relates with the wave equation. Can someone with a clear understanding of the problem explain it to me in simple terms?

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2 Answers 2

up vote 6 down vote accepted

I'm sure Emilio Pisanty's answer is fine, +1, but it goes a little over my head. It also appeals to specific properties of electromagnetic waves, whereas the ray approximation is much more general than that. Here's a simpler plausiblity argument that may be more at the level that the OP can understand.

If you diffract a wave through a slit of width $w$, you get a diffraction pattern with an angular width $\theta$ of order $\lambda/w$ (in radians). When $\lambda$ is small compared to $w$, $\theta$ gets small. In the limit where $\lambda/w\rightarrow0$, $\theta\rightarrow0$, and you have a ray coming through the slit. Different types of waves (water waves, sound waves, light waves, ...) will have different details relating to things like polarization, but none of that affects the above argument.

If it is so, it should obey to the wave equation and this doesn't seem to me to describe a straight line ray.

Right. A perfectly collimated, parallel wave train can never be a solution of the wave equation. However, a diffraction pattern with a very small angular width can be a solution, and if the width is small enough, it's indistinguishable from a parallel wave train.

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Thank you Ben, +1 to Emilio's answer that I believe to be the most comprehensive of all but that, unfortunately, I'm unable to comprehend. This is more at my level –  Marco A. May 21 '13 at 9:54
    
By "diffraction pattern with small angular width", you mean only the central great maxima, right? And say for example, we talk of a beam of light and not just a single ray, how can the minimization of the central maxima to a point show the geometric limit of the beam, i.e. how can a beam through a large slit be dealt as in geometric optics, by considering the minimization of the width of central maxima? –  Satwik Pasani Dec 20 '13 at 8:38

Light rays are only a good way to describe light in the limit of very short wavelengths, as compared to all other length scales in the problem. This is called the geometric-optics limit, and there one can solve the Maxwell equations in what's called the eikonal approximation to obtain Fermat's Principle and thus a light-ray description of light.

The essential point of the eikonal approximation is to make an Ansatz of the form $$E(\mathbf x,t)=E_0 e^{i(\chi(\mathbf x)-\omega t)}$$ for the electric field. Here I'm ignoring the vector nature of light, and multichromatic fields, but what follows generalizes well. Other than that, the Ansatz is quite general. In these terms, the wave equation reads $$-i\nabla^2\chi+\| \nabla \chi\|^2= \frac{n^2\omega^2}{c^2}.$$ The eikonal approximation then consists of neglecting the first term. The rationale for that is that in the short-wavelength limit $\chi$ contains a term of the form $\mathbf k\cdot \mathbf x$ which makes $\nabla\chi$ very big in comparison to $\nabla^2\chi$, which measures spatial variations in the envelope and which is therefore "small".

Once you do that, you get the eikonal equation, which reads $$\| \nabla \chi\|^2= \frac{n^2\omega^2}{c^2}.$$ (By the way, this has a very interesting counterpart in classical mechanics, the Hamilton-Jacobi equation.) The trajectories of light rays can then be defined as the integral curves of the gradient $\nabla\chi$, i.e. trajectories $\mathbf r=\mathbf r(s)$, parametrized by path length, which follow $$\frac{d\mathbf r}{ds}=\frac{\nabla \chi}{n\omega/c}.$$ These trajectories are orthogonal to the wavefronts, which are surfaces of constant $\chi$, propagate in straight lines in free space, and interact with optical elements the way you'd expect them to: for all the world, they're light rays.

For some more mathematical detail, see this question. If the above is still too complicated, let me know.

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+1 just for mentioning one of my favourite analogies in physics: eikonal equation vs Hamilton-Jacobi equation! (and, of course, for the good answer) –  Alex A May 20 '13 at 22:16

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