# if a simple pendulum is dropped in a elevator with a acceleration greater than acceleration due to gravity then what will be its frequency

if a simple pendulum is dropped in a elevator with a acceleration greater than acceleration due to gravity then what will be its frequency ? We know time period depends on frequency.

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How can we drop pendulum with more than $g$ acceleration? –  ABC May 19 '13 at 9:48
I'm guessing that the elevator is "dropped", with a small rocket on the elevator roof (thrusting downward) –  User58220 May 19 '13 at 18:45

Same formula as usual but with the difference that. $$g\rightarrow g\pm g'$$ where $g'$ is the acceleration of the elevator. The plus sign is used if the two accelerations are in different directions... Thus if elevator free fall then $g-g'=0$ and the period goes to infinity.

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