Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

This is really bugging me. When you look up some educational text about stars life, this is what you find out:

  1. Gravity creates the temperature and pressure to start fusion reactions.
  2. The fusion proceeds to heavier and heavier cores ending with iron, which remains in the centre of the star.
  3. One moment, all light cores are depleted and the gravity wins over the power of the fusion reactions, now absent.
  4. The core of the star collapses into high density object, which may vary depending on the star mass.
  5. And the top layers of the star explode.

And I just cannot find clear explanation why. According to what I imagine, the top layers of the star should just fall into the collapsing core.

Is that because of the 3rd Newtons rule?

Or do the stars have some need to end with a cool boom?

share|improve this question
2  
The external layers do fall into the collapsing core before exploding. I'm not really into this kind of subject, but since I know some people that are researching SN explosions, I can ask on a reference, if you like. As far as I could understand, it's highly non-trivial why the external layers ends up exploding, and it seem to involve lots of different mechanisms working together. So, I believe that you have all the right to be intrigued by that. –  Hydro Guy May 6 '13 at 22:17
1  
I'm looking forward to any explanation. –  Tomáš Zato May 6 '13 at 22:40
    
I believe the explanation comes from the creation of a shockwave originated by the collapse of the outer layers into the massive core. –  PML May 6 '13 at 22:51
2  
Has anyone managed to make a model that reliably explodes when an explosion is expected? I remember it being a major problem when I was an undergrad a decade ago. –  Dan Neely May 7 '13 at 13:59

3 Answers 3

up vote 36 down vote accepted

There are lots of possible ways that stars can end their life, even in the subset of cases where the end is violent. Eloff has given an excellent answer, but I wanted to add a few points.

Summary (tl;dr):

You need the right conditions (mass, angular momentum, metallicity, etc) to produce a proto-neutron-star which is able to resist complete collapse to a black-hole. The bounce from hitting that proto-neutron-star surface, and the heating from neutrinos, is what drives the explosion of material. Radioactivity is eventually the source of the light we see from supernovae.


The basic picture for producing a supernova from a massive star1:

  1. The star burns progressively heavier elements on shorter timescales until producing iron (Fe) on the timescale of seconds.

  2. After iron, fusion in the core ceases, and pressure support is lost. Gravity is unhindered, and the star begins dynamical collapse.

  3. As the Fe-core contracts, electron-capture begins to convert protons + electrons into neutrons, emitting GeV neutrinos.

  4. The Fe-core, now largely composed of neutrons is stabilized to further collapse by neutron degeneracy pressure at nuclear densities.

  5. Material further out, which is still collapsing, hits the incredibly hard proto-neutron-star surface - causing a bounce (see video analog): the launch of a powerful shockwave outwards through the star.

  6. Because the neutrinos produced from electron-capture are so energetic (as dmckee points out), and because the densities are so high - the neutrinos are able to deposit significant amounts of energy into the outer-material, accelerating it beyond escape velocities. This is the supernova explosion.

  7. Due to the hot, dense, nucleon-rich nature of the ejecta, r(apid)-process nucleosynthesis produces radioactive Nickel (Ni) and Cobalt (Co).

  8. After roughly 10's of days, the expanding supernova ejecta becomes optically thin - allowing the radiation produces by Ni and Co decay to escape - this causes the optical emission we call a supernovae.

chart of supernova stages

from http://arxiv.org/abs/astro-ph/0612072

Why does a supernova explode?

All massive stars are not believed to produce supernovae when they explode. In the following figure (which is intended to convey the basic idea - but not necessarily the quantitative aspects), regions titled 'direct black-hole formation' are regions of initial mass where the neutron-degeneracy pressure (stage '4' above) is insufficient to halt collapse. The Fe core is massive enough that it continues collapsing until a black-hole is formed, and most of the material further out is rapidly accreted.

The region in this plot between about 8 and 35 solar masses is where the vast majority of observed supernovae are believed to come from.

To answer why supernovae explode: Consider the schematic process outlined above. The reason why some deaths-of-massive-stars explode and others don't, is that you need the right conditions (mass, angular momentum, metallicity, etc) to produce a proto-neutron-star which is able to resist complete collapse. The bounce from hitting that proto-neutron-star surface, and the heating from neutrinos is what drives the explosion of material. Radioactivity is eventually the source of the light we see from supernovae.

plot of relationship between initial and final stellar mass

from http://rmp.aps.org/abstract/RMP/v74/i4/p1015_1


Footnote

1: This discussion is constrained to 'core collapse' supernovae - the collapse of massive stars, observed as type Ib, Ic, and type II supernovae

Additional References

Basically any paper by or with Stan Woosley, e.g.
http://arxiv.org/abs/astro-ph/0601261

http://www.mpia-hd.mpg.de/homes/semenov/Lectures/Heidelberg_Uni_2012/Lecture7_Basics_of_SF_Stellar_Nucleosynthesis.pdf

share|improve this answer

You're correct that when fusion reactions decrease past a certain point because the fuel is used up, the outward pressure created by the fusion no longer counteracts the gravitational forces and the star collapses (rapidly) in on itself. In stars of the right mass (smaller than about 15 solar masses, but large enough to collapse into a neutron star) the compacting core is heating up to insane temperatures of around 100 billion kelvin. This overwhelms the neutron degeneracy pressure that's preventing the star from collapsing further and a huge burst of neutrinos is released. About 10% of the star's mass/energy is released in around 10 seconds, which is a mind-boggling amount of energy.

This is where it gets fuzzy, according to wikipedia:

The suddenly halted core collapse rebounds and produces a shock wave that stalls within milliseconds in the outer core as energy is lost through the dissociation of heavy elements. A process that is not clearly understood is necessary to allow the outer layers of the core to reabsorb around 10^44 joules (1 foe) from the neutrino pulse, producing the visible explosion, although there are also other theories on how to power the explosion.

So it seems it's this sudden neutrino pulse that's reabsorbed by the outer-core that triggers the explosion.

share|improve this answer
2  
It is worth noting that the neutrinos produced in a supernova are mostly at a few GeV energies where their interaction cross-sections are roughly a factor of 1000 higher than those of typical solar neutrinos---that's enough that a small but significant fraction of the energy is deposited in the outer layers of the star. –  dmckee May 6 '13 at 23:29
    
@dmckee also I'm just speculating here, but I'd imagine the high density of the matter in the outer core would mean more neutrino interactions than with neutrinos passing through the earth? –  Eloff May 7 '13 at 23:10
    
Yes, it goes essentially by the matter density too. –  dmckee May 7 '13 at 23:19

This "bounce" theory isn't logical. 1. How strong that bounce must be so it can escape such strong gravity and eject very heavy outer layers of the core? 2. For something to bounce it must be elastic in some way or hit elastic surface. What is elastic in this case? 3. Another thing that's bothering me is what happens with bouncing when the core is much denser and shrinks to black hole? Where is bounce in that case?

So, I think that supernova is nothing but colossal neutrino explosion with totaly insignificant or in best case very small bounce effect.

share|improve this answer
5  
You know, people didn't just sit around and say "hey, I bet it bounces" without doing a lot of theoretical work and simulations. You've thrown out the bounce idea based on what evidence or simulation or alternative? –  Brandon Enright Feb 18 at 23:07

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.