# Apparent and real depth object in water [closed]

Did I get my formula right? Seems like the correct answer is $d_o = 1.33 \times d_i$ but I thought the formula I should use is $d_i = - \frac{n_2}{n_1} d_o$

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## closed as too localized by John Rennie, Qmechanic♦May 5 '13 at 12:09

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we have the formula

n = real depth/apparent depth

so, real depth = n * apparent depth = 1.33 * o.4 = 0.532 so right ans may be D

here n is refractive index of water with respect to air

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Hmm ... maybe I missed out this formula? But is the formula I have correct? If so why cant I get the right answer? Any ideas? –  Jiew Meng May 5 '13 at 9:55
Also if we had such a formula, then the other n must be vacuum? –  Jiew Meng May 5 '13 at 9:56
Oh I got it ... $n_2$ is on the other side of the object! –  Jiew Meng May 5 '13 at 9:59
Narendra, please keep in mind for the future that our homework policy prohibits posting complete answers to homework questions. Ordinarily this would be temporarily deleted, but in this case it's already been seen so there would be little point. Just please don't post such answers in the future. –  David Z May 5 '13 at 19:23