I'm working on a problem regarding two objects with the same kinetic energy.
Two objects with masses of $m_1$ and $m_2$ have the same kinetic energy are both moving to the right. The same constant force F is applied to the left to both masses. If $m_1=4m_2$, the ratio of the stopping distance of $m_1$ to that of $m_2$ is:
I believe the key information here is that both objects have the same kinetic energy. This must mean that an equal amount of work (force $\times$ distance) must be applied to each object in order to bring it to a complete stop ($KE + q = 0$)?
Is the correct answer $1:1$?