If the area under an acceleration-time graph denotes velocity and the area under a velocity-time graph denotes displacement, what exactly does the area under a displacement-time graph denote?
I think it just represents what you said: the area under a displacement-time graph. I can't think of any other use for it. There are two main reasons for this:
I don't see this quantity computed very often so I don't think it is that useful, but here is one thing that can be said: If $A$ is the area under the graph and $T$ is the duration of time over which the integral was preformed then $A/T$ is the average displacement from the origin during that interval of time.
protected by Qmechanic♦ Nov 5 '15 at 19:00
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