Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

[1] A very simple example of feynman rule for scalar fields.

After computing the diagram i have got the following:

$$ -i(2\pi)^4g^2\int d^4q \frac{i}{q^2 -m^2c^2}\delta^{(4)}(p_1 - p_3 -q) \delta^{(4)}(p_2 + q -p_4) $$

I'm a little confused about how the integral approached, it integrated over one delta function to get

$$ -ig^2\frac{1}{(p_4 - p_2)^2 -m^2c^2}(2\pi)^4\delta^{(4)}(p_1+p_2 - p_3 - p_4) $$

Am i allowed to do that? I mean I have $q$ in both delta functions. Can I just integrate over one of it? It doesn't sound right. What I'm missing here?

share|improve this question
    
If you like this question you may also enjoy reading this Phys.SE post. –  Qmechanic Apr 18 '13 at 13:39
add comment

1 Answer

up vote 4 down vote accepted

That looks correct to me. Consider the basic property of the delta functions $$ \int dx f(x) \delta(x-a) = f(a). $$ Nothing forbids $f(x)$ to be a composite function, for example $f(x) \equiv g(x)\delta(x-b)$, so $f(a) = g(a) \delta(a-b)$. Hence we get, $$ \int dx f(x) \delta(x-a) \equiv \int dx \, g(x)\delta(x-b) \delta(x-a) = g(a)\delta(a-b). $$

share|improve this answer
    
Thanks for the answer. –  Aftnix Apr 18 '13 at 13:09
    
@Aftnix: The factor of $\delta^{(4)}(p_{\mathrm{final}}-p_{\mathrm{initial}})$ is common to all scattering amplitudes, whether it be string theory or QED. It ensures momentum conservation. You can define new Feynman rules to get rid of the delta functions altogether, and just compute the part that changes based on the process which you need for cross sections, decay rates, etc. –  JamalS Apr 9 at 19:38
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.