# Bremsstrahlung vs energy conservation

From Wikipedia:

Bremsstrahlung is electromagnetic radiation produced by the deceleration of a charged particle when deflected by another charged particle, typically an electron by an atomic nucleus. The moving particle loses kinetic energy, which is converted into a photon because energy is conserved.

Isn't energy conserved for the moving particle in an electrostatic potential, $E_{kinetic} + E_{potential} = \frac{mv^2}{2}+\frac{kqQ}{r}$? If so, where does the extra energy for photons come from?

Why don't electrons in atoms radiate away their energy?

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"Isnt energy conserved for the moving particle, kinetic + potential, if so, where does the extra energy for photons come from?": "The moving particle loses kinetic energy, which is converted into a photon because energy is conserved." You have both asked and answered this question. –  Michael Brown Apr 17 '13 at 23:15
Hi errr: Do you have log-in problems? It might help to register your account. –  Qmechanic Apr 17 '13 at 23:41