# Electrical energy storage in superconductors

I am a first year A-level student and I am doing a project about the possibility of storing electrical energy in a superconductor. I have researched and I am aware of the critical current density and the critical magnetic field of different superconductors, where the magnetic field created by the wire (Ampere’s law) interacts with the magnetic field of the superconductor (Meissner effect). But, if I had a loop of superconductor and I cool it down enough (with that I mean enough so its resistance becomes completely 0) then could I use a huge voltage and a relatively small current (not big enough to reach its critical current) in order to store electrical energy in the superconductor?

If it is not possible I would like to know why not and if it is possible I would like to know why we are not using it nowadays as a form of storing electrical energy (is it only the practical issues of cooling it down)?

Thank you very much

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Because of the zero resistivity, you can not apply a huge voltage on a superconductor. – Everett You Apr 17 '13 at 1:19

I think you're getting mixed up with the power dissipated in a circuit. For some (resisitive) circuit the power dissipated is given by $W = IV$, so for the same power dissipation you can have large $I$ and small $V$ or small $I$ and large $V$. But we aren't talking about power dissipation: we are talking about power storage. The only circuit elements that store power are capacitors or inductors, that store power as electric and magnetic fields respectively. – John Rennie Apr 17 '13 at 9:18