Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

According to Sommerfeld the derivative of the density of states $g'(\varepsilon)$ apears in several thermodynamic quantities. Will this also be the case if one use the correct dispersion relation of crystal? If yes don't we encounter the divergence in these quantities when we pass a van Hove singularity (where $g'(\varepsilon)\rightarrow \infty $)?

share|cite|improve this question
For the logarithmic and weaker singularities that van Hove singularities give rise to in two and three dimensional crystals, $g'(\epsilon)$ will be discontinuous at the critical frequency of any van Hove singularity, so yes, you are quite right. Which quantities did you have in mind? – Chay Paterson Jun 27 '13 at 18:14

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Browse other questions tagged or ask your own question.