If emissivity and reflectivity are inversely proportionate, why does glass have a high emissivity of around 0.95-0.97 as well as being very reflective for IR Radiation?
normally it works but not with glass!
Can anyone explain this?
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In an isothermal steady state condition, meaning when the temperature is uniform and not changing with time,
%Reflected + %Transmitted + % Absorbed = 100%
For opaque system,
%Reflected + % Absorbed = 100% .........(1)
Now, if the object absorbs infrared radiation, its energy (and thus temperature) will increase, but as the object is in steady state, to offset that increase in temperature, the rate of emission must be equal to the rate of absorption. So,
% Absorbed = % Emitted.
Substituting in equation (1),
%Reflected + % Emitted = 100% .........(2).
So reflectivity is reciprocal to emissivity.
For translucent system,
%Reflected + %Transmitted + % Emitted = 100%.........(3).
This is the associated physics.
It is true for glass also, only transmissivity comes into picture, but still, reflectivity is reciprocal to emissivity.
According to this article the lenses on thermal cameras are not made from glass, but rether from Germanium, CZinc Selenide or Zinc Sulfide. These materials are not transparent to light so it's quite reasonable for them to have a high reflectivity.
Response to comment:
The emissivity and reflectivity only have to add up to one at the same wavelength. So if the emissivity is high for infra-red that doesn't clash with the reflectivity being high for visible light. This (or rather it's converse) is exactly why greenhouses heat up in visible light. They have a high emissivity and low reflectivity at visible wavelengths but a low emissivity and high reflectivity at IR wavelengths.
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Based on the experiments you describe in the comments, it seems like you might very well have a reflectivity of 20-30% in your window, for the spectral region where your camera measure. The question is where you got the high emissivity numebers from. It seems likely that the problem is that you're assuming the emissivity and reflectivity is the same throughout the infrared region. The high emissivity might be for another part of the spectrum than where your camera measure.