I am trying to solve the following problem on capacitors:
I have to find the total energy loss when all three switches are closed, and subsequent equilibrium attained.
I had very little idea of how to proceed, but this is what I did.
Even when the switches are closed, the sum of charges on right plate of $C_1$ and the left plate of $C_2$ $(-30\ mC)$ will remain conserved. Let the final charge appearing on on the right plate of $C_1$ be $q\ mC$, then the charge on the left plate of $C_2$ will be $(-30-q)\ mC$.
Now, will the charge on the left plate of $C_1$ and the right plate of $C_2$ be $-q\ mC$ and $(30+q)\ mC$ ?
If this is so, then I think I can obtain the value of $q$ using the Voltage Law (and therefore the energy lost).
If I am incorrect (which I suspect I am), I hope someone can point me in the right direction.