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when charging a sphere by induction using a (-) charged object , and we put it to the right side of the sphere, electrons are pushed to the left side , so we ground the left side and the excess electrons escape. but what if we grounded the right side ( which has less electrons than usual ) wouldn't electrons flow from the ground to neutralise this side?

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While you keep the (-) charged object near the sphere, the electrons that'll flow from ground to neutralise the right side will also get pushed towards the left side, though the proportion might vary.

That's what I thought. But here's another logic. If the (-) charged object can push incoming electrons from the ground to the left side of the sphere, it can also push them down to the ground i.e. it will never let the ground donate electrons to the sphere via right side due to electrostatic repulsion.

Answer: No, nothing will happen if you try to ground the right side. No neutralization, no -ve charging.

I suggest you try this out. It would be a fun experiment.

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so eventualy no longer electrons can be pushed because of the repulsion from the (-) left side then if we remove the ground and the charged object the object will be negatively charged , that what i figure out , but is it possible to induce a (-) charge using a -ve charged object? – martin Mar 11 '13 at 19:17
@martin Made an update! – Cheeku Mar 11 '13 at 23:19

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