Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

If one is in complete darkness, what is the minimum optical power that the eye can "see" (let's say in 500-600 nm range).

I found that for 510 nm, 90 photons can be detected (http://en.wikipedia.org/wiki/Absolute_threshold).

Calculating the energy for these photons and considering 150 fs pulses with 80 Mhz repetition rate, results in an average power of ~ 3 nW.

Does anyone has other sources of information about this ?

share|improve this question
    
dfisica.ubi.pt/~hgil/FotoMetria/HandBook/ch02.html There you go. –  Cheeku Mar 11 '13 at 15:15
    
There is actualy rather a lot of ambiguity in this question right now. The sensing cells in your eye can respond to single photons (though their QE is not high). However, there is a preprocessing layer (which as a particle experimenter I would describe as a hardware trigger) which discards isolated hits so they never register in the conscience mind. I assume you mean to ask about the dimmest light which can be used to make decisions. –  dmckee Mar 11 '13 at 22:01
    
@dmckee Ya, he probably means the minimum number of photons required to judge whether light is coming or not. Citing the same example,90 photons be detected for 510 nm implies that if you detect about 50 photons at 510 nm, your eyes wouldn't know that you have light from 510 nm range. –  Cheeku Mar 11 '13 at 23:26
    
Sorry for being ambiguous, by detection I meant what excites the brain and takes to the sensation of vision. I was curious if there were other similar experiments like the one provided on Wikipedia link above. –  Silviu Mar 12 '13 at 19:47
add comment

2 Answers

Albert Rose studied this question in the 1940's and developed the Rose Criterion which states that the signal-to-noise ratio ($SNR$):

$$SNR=\dfrac{\mu}{\sigma}$$

For $100$% identification of an object by the human eye is $SNR \approx 5$. He based this off of quantum arguments where he looked at the average number of photons per unit area in an photo image and stated gave the equation $\Delta N = kN^{\frac{1}{2}}$ where $\Delta N$ is the smallest perceptible change and $N$ is the average number of quanta absorbed in a pixel and $k$ is the $SNR$ (see eq 1, 1a and figure 1).

If one uses this ratio, then in two independent pixels one can distinguish one from the other if there are an average of $100$ quanta absorbed in the pixels, then one would be able to distinguish between the two, if one had $50$ quanta more than the other. This relationship has an obvious limit when the average number of quanta are $> 7$ and all the photon ($> 14$ total for two pixels) are found in one pixel and not the other, as shown in the table below.

rose

share|improve this answer
add comment

Many years ago I have read about experiments of Vavilov and collaborators who claimed to have registered single photons by the human eye. I cannot, however, recall the source.

share|improve this answer
    
    
This is the same as the info from Wikipedia from the link in the question. –  Silviu Mar 12 '13 at 20:34
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.