I have a question about the results of RG on Ising model. I know it's possible to obtain two couple of relations
- $K'(K)$, $q(K')$
- $K(K')$, $q(K)$
between the coupling costants. My problem arise when i try to draw the flow diagram of the coupling constants. I know that this model dont allow phase transition except the trivial case $T=0$, but if we reiterate the relation (1) or (2) we increase or decrease the coupling costant. In one case i obtain $$K=0,T=\infty>>>>\cdots>>>>K=\infty,T=0$$ but in the other?
Boolean Ising Model with $d=1$ dimension of lattice, $D=1$ dimension of vector space of the spins on lattice. The energy with zero external field is
$$H=-J\sum_{<ij>}S_iS_j$$ note that there are overcounting. Then the partition function can be put in the following form
$$Z=\sum_{\{S\}}\prod_ie^{KS_iS_{i+1}}$$
With a partial summation on even spins it became
$$Z'=\sum_{S}\prod_ie^{K(S_i+S_{i+1})}+e^{-K(S_i+S_{i+1})}=\sum_{S}\prod_if(K)e^{K'S_iS_{i+1}},$$
where in the last i used the scaling proprieties
$$Z(N,K)=f(K)^{N/2}Z(N/2,K').$$
The relations for $f(K)$ and $K'(K)$ are:
$$f(K)=2\cosh^{1/2}2K,$$
$$K'=\frac{1}{2}\log\cosh{2K}.$$
The extensivity of free energy states $-\beta F=\log Z=Nq(K)=\frac{N}{2}\log f(K)+\frac{N}{2}q(K')$.