Take the 2-minute tour ×
Physics Stack Exchange is a question and answer site for active researchers, academics and students of physics. It's 100% free, no registration required.

The heuristic argument for Hawking Radiation is, that a virtual pair-production happens just at the event horizon. One particle goes into the black hole, while the other can be observed as radiation.

I never quite understood this explanation. Say, a virtual pair is created. From the point of view of the "radiation particle" the other particle will need an infinite amount of time in order to reach the event horizon. But the virtual pair production violates energy conservation, so the particles can only exist for a finite amount of time (Heisenberg uncertainty principle). Then, they must annihilate each other again, without emitting any radiation.

I often heard the "explanation" that one particle "tunnels" through the event horizon. But isn't this again a flawed argument? Tunnelling is an effect known from flat spacetime and it makes particles cross potentials that they could not cross classically. How could this help to "jump over" an infinite time interval? For me it seems like superimposing ideas from flat spacetime on curved spacetime without any justification.

While I understand, that the original derivation from Hawking follows a different argument, one should, in principle, be able to attach his results to a physical process. I worked through his derivation and while I must admit that I didn't understand every step, it seems to me that a lot of assumptions have to be made along the way in order to produce the results. Also the whole derivation is based on Quantum Field Theory in curved spacetime, which stands on shaky grounds, since nobody can say, where it is valid and where not - we don't have a complete theory of Quantum Gravity and we simply can't say in which situations QFT in curved spacetime is a good approximation.

As you can see, I am really confused about this issue. Every sort of help is appreciated!

share|improve this question
add comment

1 Answer

I think your main question is how to reconcile the infinite time-to-reach-horizon needed for a particle created just outside the horizon with the fact that virtual pairs only exist for a short time before re-annihilation?

As you've correctly pointed out, the virtual pair picture is only a heuristic (as Hawking said in his original paper), a more satisfactory explanation is provided by the mapping of vacuum states between free-falling and asymptotically stationary observers. However, perhaps it might help to resolve the heuristic problems if, rather than imagining a highly localized point particle pair being created, one of which travels to the horizon, you instead imagine the fluctuation taking place in the quantum vacuum state, which is a nonlocal entity. So, due to the uncertainties, the vacuum fluctuation includes a field configuration with an outgoing electron plane wave and an infalling positron plane wave (for example). This configuration is picked out as consistent by the geometry and the outgoing particle flux is seen by the asymptotic observer.

share|improve this answer
Thanks you for the answer! I can see the problems with the heuristic justification more clearly now. The problem is then, that you have to mix (without a very good reason) concepts from flat and curved spacetime, right? The identification of a plain wave solution as a particle is only justified in flat spacetime, while there is no consistent notion of particles in curved spacetime. Isn't the heuristic argument flawed altogether, then? You can't consistently define a vacuum in curved spacetime, how can you talk about pair-pair-production then? –  stankowait Feb 25 '13 at 16:27
add comment

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.