# Projectile motion problem with upward acceleration and horizontal velocity [closed]

An electron in a cathode-ray tube is traveling horizontally at 2.10×10^9 cm/s when deflection plates give it an upward acceleration of 5.30×10^17 cm/s^2 .

B.) What is its vertical displacement during this time?

I am asking this because the answer my teacher gave is 2.3cm

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 For starters, y = y_0 + ut + 0.5at^2, where as you have omitted this 0.5 – Chris Feb 7 at 5:24 And secondly you performed a calculator error as well. See my answer below. – Chris Feb 7 at 5:28

## closed as too localized by Qmechanic♦Feb 12 at 0:17

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$y = y_0 + ut + 0.5at^2$

Since $y_0$ and $u$ are $0$, we have $y = 0.5~at^2$.

In your calculation $t = 2.95 \times 10^{-9}$, which is correct.

So, $y = 0.5\times5.30×10^{17}\times (2.95 \times 10^{-9})^2$

Therefore, $y = 2.3~\text{cm}$

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Thanks Chris. Silly mistake, need to be more careful – user1530249 Feb 7 at 5:29
No problem user1530249! – Chris Feb 7 at 5:31