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A block of weight 47.0 N is hanging from a rope. The tension from the rope is pulling upward on the block. The block is accelerating downward at a rate of 1.53 m/s2. What is the magnitude of the tension in the rope?

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1 Answer

There are two forces acting on the block:

Force due to gravity = $- 47.0 N$ (negative because it is downwards).

Force due to rope = $T$, where $T$ represents the tension force in the rope, pulling upwards.

Net Force = sum of all forces = $ma$.

Therefore,

$F_{net} = ma = -47 + T$

We know the block has a weight of 47 Newtons. We also know $Weight = g*mass$. Therefore, $mass = Weight/g = 47/9.8 = 4.8kg$. (Sometimes people just divide weight by 10)

We know the acceleration $a = -1.53$.

Therefore,

$F_{net} = -1.53\times 4.8 = -47 + T$

Therefore,

$-7.34 = -47 + T$

So,,

$T = 39.66 N$

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