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I've leant that entropy is a state of randomness, and that solids have a more structured form, therefore having less entropy.

However, I saw a YouTube comment stating the following:

a liquid NOT ALWAYS means higher entropy than a solid it depends...of the context for example, in the south pole, ice means higher entropy, because Mother Nature sets the equilibrium for liquid water to become ice.

Is there justification for this statement? Is it true that even in a more ordered substance like the ice, there is more entropy?

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"in the south pole, ice means higher entropy,.." Its true in following sense:- At south pole temperature of surroundings is below zero degrees i.e. <273K. Now consider ice and water in equilibrium at 273K. If water can lose some of its heat to the surrounding to form ice, then the entropy of total system ice+water+surrounding will increase. So the exact statement should be : "in south pole formation of ice is entropically favored". –  user10001 Jan 30 '13 at 19:39
    
In the South Pole or ANY other place as well, where ice is melting into water... There is nothing special about the South Pole, nothing more than in my glass of Coca-Cola with ice. –  Eduardo Guerras Valera Jan 31 '13 at 10:12
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2 Answers 2

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Let's consider the following situation. Suppose we have an ice block of mass $m$ sitting at $T=0^\circ\,\mathrm C$ in a container. To melt the ice, we need to heat it up, and the exact amount of heat we need is the so-called "latent heat of fusion" of the ice, and is given by $$ Q=mL $$ where $L$ is called the specific latent heat and is specific to the melting substance. The change in entropy of the system during the phase change is, in this case, given by the heat absorbed by the ice divided by its temperature (note here that temperature should be written in Kelvin for the following to be valid which is why we're not dividing by zero) $$ \Delta S = \frac{Q}{T}=\frac{mL}{T} $$ which is positive. This shows that the entropy of an amount of ice at $0^\circ\,\mathrm C$ is less than the entropy of the same amount (mass) of water at $0^\circ\,\mathrm C$.

I'm not sure what the YouTube comment is referring to.

For more info, see this and this.

Cheers!

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The youtube commenter is probably equating "entropy always increases" with "since the water froze (i.e. went from solid to liquid) it's entropy must have gone up" with considering that the water was exchanging heat with something else while that happened. Not an uncommon misunderstanding. –  dmckee Jan 30 '13 at 19:06
    
Alright, makes sense! I suppose then that in an isolated system with water and ice, the liquid loses entropy to heat the ice to equilibrium, but the ice gains more entropy than the liquid lost, thereby increasing the total entropy? Also, when it's not about melting, what is the value of Q and how is it found? –  DarkLightA Jan 30 '13 at 19:09
    
@dmckee Oh that's interesting; I've never encountered that particular misunderstanding, but I can definitely see how that could be confusing to someone learning about entropy for the first time and hearing the phrase "entropy always increases." –  joshphysics Jan 30 '13 at 19:09
    
I truly appreciate you taking the time to help. Also.. (Sorry, just trying to understand this) would a cube ice spontaneously forming in an above-0 degree system of water at equilibrium decrease the total entropy? –  DarkLightA Jan 30 '13 at 19:13
    
Hang on, is it maybe not possible to report entropy like that? Is it only a measure of total "randomness" of a system? Or can you say that the ice has a lower entropy than the water? –  DarkLightA Jan 30 '13 at 19:30
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In the case of the ice in the Antarctic this isn't really true. As dmcee commented on joshphysics' answer, what happens when water freezes under normal circumstances is that the entropy of the water itself drops as it becomes ice, but at the same time heat is released, and this increases the entropy of the surroundings. So the total entropy increases, but the entropy of the ice is still lower than the surrounding water. In thermodynamics, when we talk about the entropy of a system, we always mean just the entropy that's inside the system, not including the entropy of its environment. The only exception to this is when we say "entropy always increases", in which case we do mean the total entropy!

However, it is possible for ice to have a higher entropy than water under some circumstances. If you take very pure water and cool it very carefully, it is possible for it to become supercooled, as in this video. Supercooled water stays liquid even though it's below its freezing point, but if you shake it or add a small particle of dust then ice crystals will form. This will happen even if the supercooled water is in an insulated container, so that it cannot increase the entropy of its surroundings by heating them up. In this case heat is still released, but it just increases the temperature of the system. So the ice that forms is slightly warmer than the supercooled water that it comes from, but it's still below the freezing point. Since this is a spontaneous process taking place in an isolated system, it must increase the entropy, and so we can conclude that the solid ice has a higher entropy than the liquid supercooled water.

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