# Residues in QFT propagator

It is a well known fact that the location of the pole of a propagator (in QFT) can be interpreted as the physical mass.

Is there an interpretation for the residue of the propagator?

Note: I´m thinking of generalised propagator, not necessarily a propagator of a fundamental field.

-
+1, interesting question. The residue theorem is a special type of Stokes theorem, are you sure that the pole is interpreted as the mass and not the residue? The pole is an infinity, but the residue gives the pole a value (for integrable poles), or any closed closed loop the value of the pole. Intuitively it would seem to give a sort of measure of the mass? I'm not an expert in QFT or QM however... – daaxix Dec 31 '12 at 22:51
@daaxix it's the location of the pole, not the value of the pole, that gives the mass of the particle. – David Z Dec 31 '12 at 23:27
@DavidZaslavsky, ah, ok. Well the residue gives the value of the pole itself. Is there a difference between integrable and non-integrable poles in QFT? Are they all integrable? – daaxix Dec 31 '12 at 23:32
There are sometimes branch cuts in propagators, but I couldn't tell you that much about them offhand. Other than that, I can't think of any examples of nonintegrable poles. Generally, a propagator is of the form $\frac{\text{stuff}}{p^2 - m^2}$, and the residue depends on the stuff in the numerator, so it doesn't necessarily correspond to a particular physical quantity that I know of. – David Z Jan 1 '13 at 0:08