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I have a question regarding the optical constants of noble metals.

According to Johnson and Christy's paper Optical Constants of Noble Metals (Phys. Rev. B 6, 4370–4379 (1972), doi:10.1103/PhysRevB.6.4370), in the Drude free electron theory the equation for the dielectric permittivity is $$\epsilon(\omega)=1-\frac{\omega_p^2}{\omega(\omega+i/\tau)}=1-\frac{\omega_p^2}{\omega(\omega+i\gamma)},$$ where $\epsilon(\omega)$ is the dielectric constant at frequency $\omega$, $\omega_p$ the plasma frequency, and $\gamma=1/\tau$ the collision frequency.

In the nanohub photonics database the constants can be calculated from different theoretical and experimental models.

However, in CST Microwave Studio I need to give the epsilon infinity value, which really comes from modified drude model: $$ε=ε(\infty)-\frac{ω_p^2}{ω^2+iγω}.$$ How do I get the value of $\epsilon(\infty)$ for gold? Is there any reference by using which we can directly convert the free electron theory Drude model to the modified Drude model?

I am specifically searching for the values of $ε(\infty)$, $ω_p$, and $γ$ for gold in the 700nm to 1100 nm range (specifically 830nm).

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Welcome, you can use latex by putting formula between two $ signs. Also I have added a link to the article you mentioned. – hwlau Dec 16 '12 at 21:21

1 Answer

$$ \epsilon_\infty=9.5 $$ $$ \omega_P=1.36\times 10^{16} \text{ rad/s} $$ $$ \gamma=1.05\times 10^{14} \text{ rad/s} $$

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Two things. First, this doesn't seem to answer the question which was "How do I get the the value of... ?", and secondly we have the MathJax rendering engine active on the site which allows you to write LaTeX-alike markup for mathematics. I'll do this post for you. – dmckee Feb 27 at 0:46
Indeed the question is about the way to get an answer, not about the answer itself (pretty much always, otherwise it doesn't belong on SE) – michielm Feb 27 at 7:07
@dmckee is right. This answer of values is part of the question. The focus of OP's question is $\epsilon(\infty)$. In other words: Whats the dielectric permittivity for low wavelenghts? In this regime below the cut-off plasma frequency $\omega_p$ there is no transmission. I don't understand the relation to your $\lambda_{min}=700\,$nm (red) area of interest. Could you please explain? – Stefan Bischof Mar 21 at 15:18

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